这个问题在这里已有答案：
我需要能够使用jQuery在今天的日期添加1,2,5或10天。
你可以使用JavaScript，不需要jQuery：
var someDate = new Date();
var numberOfDaysToAdd = 6;
someDate.setDate(someDate.getDate() + numberOfDaysToAdd);
格式化为dd/mm/yyyy：
var dd = someDate.getDate();
var mm = someDate.getMonth() + 1;
var y = someDate.getFullYear();
var someFormattedDate = dd + '/'+ mm + '/'+ y;
如果不需要日期中的时间，那么您只需使用日期对象的方法来提取月，年和日，并向日部分添加“n”天数。
var n=5; //number of days to add.
var today=new Date(); //Today's Date
var requiredDate=new Date(today.getFullYear(),today.getMonth(),today.getDate()+n)
编辑：参考：Mozilla JavaScript Date
function addDays(n){
var t = new Date();
t.setDate(t.getDate() + n);
var month = "0"+(t.getMonth()+1);
var date = "0"+t.getDate();
month = month.slice(-2);
date = date.slice(-2);
var date = date +"/"+month +"/"+t.getFullYear();
alert(date);
}
addDays(5);您可以使用此库“Datejs开源JavaScript日期库”。
我发现这是javascript的痛苦。看看这个帮助我的链接。你有没有想过扩展日期对象。
http://pristinecoder.com/Blog/post/javascript-formatting-date-in-javascript
/*
* Date Format 1.2.3
* (c) 2007-2009 Steven Levithan <stevenlevithan.com>
* MIT license
*
* Includes enhancements by Scott Trenda <scott.trenda.net>
* and Kris Kowal <cixar.com/~kris.kowal/>
*
* Accepts a date, a mask, or a date and a mask.
* Returns a formatted version of the given date.
* The date defaults to the current date/time.
* The mask defaults to dateFormat.masks.default.
*/
var dateFormat = function () {
var token = /d{1,4}|m{1,4}|yy(?:yy)?|([HhMsTt])\1?|[LloSZ]|"[^"]*"|'[^']*'/g,
timezone = /\b(?:[PMCEA][SDP]T|(?:Pacific|Mountain|Central|Eastern|Atlantic) (?:Standard|Daylight|Prevailing) Time|(?:GMT|UTC)(?:[-+]\d{4})?)\b/g,
timezoneClip = /[^-+\dA-Z]/g,
pad = function (val, len) {
val = String(val);
len = len || 2;
while (val.length < len) val = "0" + val;
return val;
};
// Regexes and supporting functions are cached through closure
return function (date, mask, utc) {
var dF = dateFormat;
// You can't provide utc if you skip other args (use the "UTC:" mask prefix)
if (arguments.length == 1 && Object.prototype.toString.call(date) == "[object String]" && !/\d/.test(date)) {
mask = date;
date = undefined;
}
// Passing date through Date applies Date.parse, if necessary
date = date ? new Date(date) : new Date;
if (isNaN(date)) throw SyntaxError("invalid date");
mask = String(dF.masks[mask] || mask || dF.masks["default"]);
// Allow setting the utc argument via the mask
if (mask.slice(0, 4) == "UTC:") {
mask = mask.slice(4);
utc = true;
}
var _ = utc ? "getUTC" : "get",
d = date[_ + "Date"](),
D = date[_ + "Day"](),
m = date[_ + "Month"](),
y = date[_ + "FullYear"](),
H = date[_ + "Hours"](),
M = date[_ + "Minutes"](),
s = date[_ + "Seconds"](),
L = date[_ + "Milliseconds"](),
o = utc ? 0 : date.getTimezoneOffset(),
flags = {
d: d,
dd: pad(d),
ddd: dF.i18n.dayNames[D],
dddd: dF.i18n.dayNames[D + 7],
m: m + 1,
mm: pad(m + 1),
mmm: dF.i18n.monthNames[m],
mmmm: dF.i18n.monthNames[m + 12],
yy: String(y).slice(2),
yyyy: y,
h: H % 12 || 12,
hh: pad(H % 12 || 12),
H: H,
HH: pad(H),
M: M,
MM: pad(M),
s: s,
ss: pad(s),
l: pad(L, 3),
L: pad(L > 99 ? Math.round(L / 10) : L),
t: H < 12 ? "a" : "p",
tt: H < 12 ? "am" : "pm",
T: H < 12 ? "A" : "P",
TT: H < 12 ? "AM" : "PM",
Z: utc ? "UTC" : (String(date).match(timezone) || [""]).pop().replace(timezoneClip, ""),
o: (o > 0 ? "-" : "+") + pad(Math.floor(Math.abs(o) / 60) * 100 + Math.abs(o) % 60, 4),
S: ["th", "st", "nd", "rd"][d % 10 > 3 ? 0 : (d % 100 - d % 10 != 10) * d % 10]
};
return mask.replace(token, function ($0) {
return $0 in flags ? flags[$0] : $0.slice(1, $0.length - 1);
});
};
}();
// Some common format strings
dateFormat.masks = {
"default": "ddd mmm dd yyyy HH:MM:ss",
shortDate: "m/d/yy",
mediumDate: "mmm d, yyyy",
longDate: "mmmm d, yyyy",
fullDate: "dddd, mmmm d, yyyy",
shortTime: "h:MM TT",
mediumTime: "h:MM:ss TT",
longTime: "h:MM:ss TT Z",
isoDate: "yyyy-mm-dd",
isoTime: "HH:MM:ss",
isoDateTime: "yyyy-mm-dd'T'HH:MM:ss",
isoUtcDateTime: "UTC:yyyy-mm-dd'T'HH:MM:ss'Z'"
};
// Internationalization strings
dateFormat.i18n = {
dayNames: [
"Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat",
"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"
],
monthNames: [
"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec",
"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"
]
};
// For convenience...
Date.prototype.format = function (mask, utc) {
return dateFormat(this, mask, utc);
};
我发现当你使用new Date(nYear, nMonth, nDate);时，JavaScript可以返回正确的日期。当你使用它时，尝试查看dDate变量的结果：
var dDate = new Date(2012, 0, 34); // the result is 3 Feb 2012
我有一个SkipDate函数可以分享：
function DaysOfMonth(nYear, nMonth) {
switch (nMonth) {
case 0: // January
return 31; break;
case 1: // February
if ((nYear % 4) == 0) {
return 29;
}
else {
return 28;
};
break;
case 2: // March
return 31; break;
case 3: // April
return 30; break;
case 4: // May
return 31; break;
case 5: // June
return 30; break;
case 6: // July
return 31; break;
case 7: // August
return 31; break;
case 8: // September
return 30; break;
case 9: // October
return 31; break;
case 10: // November
return 30; break;
case 11: // December
return 31; break;
}
};
function SkipDate(dDate, skipDays) {
var nYear = dDate.getFullYear();
var nMonth = dDate.getMonth();
var nDate = dDate.getDate();
var remainDays = skipDays;
var dRunDate = dDate;
while (remainDays > 0) {
remainDays_month = DaysOfMonth(nYear, nMonth) - nDate;
if (remainDays > remainDays_month) {
remainDays = remainDays - remainDays_month - 1;
nDate = 1;
if (nMonth < 11) { nMonth = nMonth + 1; }
else {
nMonth = 0;
nYear = nYear + 1;
};
}
else {
nDate = nDate + remainDays;
remainDays = 0;
};
dRunDate = Date(nYear, nMonth, nDate);
}
return new Date(nYear, nMonth, nDate);
};
这是一个适合我的解决方案。
function calduedate(ndays){
var newdt = new Date(); var chrday; var chrmnth;
newdt.setDate(newdt.getDate() + parseInt(ndays));
var newdate = newdt.getFullYear();
if(newdt.getMonth() < 10){
newdate = newdate+'-'+'0'+newdt.getMonth();
}else{
newdate = newdate+'-'+newdt.getMonth();
}
if(newdt.getDate() < 10){
newdate = newdate+'-'+'0'+newdt.getDate();
}else{
newdate = newdate+'-'+newdt.getDate();
}
alert("newdate="+newdate);
}
你可以尝试这个，不需要JQuery：timeSolver.js
例如，今天添加5天：
var newDay = timeSolver.add(new Date(),5,"day");
你也可以按小时，月等添加。请参阅更多信息。
您可以像这样扩展javascript Date对象
Date.prototype.addDays = function(days) {
this.setDate(this.getDate() + parseInt(days));
return this;
};
并在您的javascript代码中，您可以调用
var currentDate = new Date();
// to add 4 days to current date
currentDate.addDays(4);
为什么不简单地使用
function addDays(theDate, days) {
return new Date(theDate.getTime() + days*24*60*60*1000);
}
var newDate = addDays(new Date(), 5);
或-5删除5天
这是5天：
var myDate = new Date(new Date().getTime()+(5*24*60*60*1000));
你不需要JQuery，你可以在JavaScript中完成它，希望你能得到它。
Moment.js
从moment.js安装here。
npm：$ npm i --save moment
凉亭：$ bower install --save moment
下一个，
var date = moment()
.add(2,'d') //replace 2 with number of days you want to add
.toDate(); //convert it to a Javascript Date Object if you like
链接参考：http://momentjs.com/docs/#/manipulating/add/
Moment.js是一个令人惊叹的Javascript库，用于管理日期对象和40kb极轻的重量。
祝好运。
来自Krishna Chytanya的原型解决方案非常好，但需要一个小的但重要的改进。必须将days param解析为Integer，以避免在days为类似“1”的字符串时进行奇怪的计算。 （我需要几个小时才能找到，我的申请出了什么问题。）
Date.prototype.addDays = function(days) {
this.setDate(this.getDate() + parseInt(days));
return this;
};
即使您不使用此原型函数：使用setDate（）时务必确保使用Integer。
这里接受的答案给了我不可预知的结果，有时奇怪地增加了几个月和几年。
我能找到的最可靠的方法是在这里找到Add days to Javascript Date object, and also increment month
var dayOffset = 20;
var millisecondOffset = dayOffset * 24 * 60 * 60 * 1000;
december.setTime(december.getTime() + millisecondOffset);
编辑：虽然它对一些人有用，但我认为这不完全正确。我建议使用更流行的答案或使用像http://momentjs.com/这样的东西
纯JS解决方案，日期格式为YYYY-mm-dd格式
var someDate = new Date('2014-05-14');
someDate.setDate(someDate.getDate() + 15); //number of days to add, e.x. 15 days
var dateFormated = someDate.toISOString().substr(0,10);Date.prototype.addDays = function(days)
{
var dat = new Date(this.valueOf() + days * 24 * 60 * 60 * 1000 );
return dat;
}