当我在shell上运行命令echo /tmp/stderr{,.pub} | xargs -n 1 ln -sf /dev/stderr && yes | ssh-keygen -t ed25519 -C "" -N "" -f /tmp/stderr > /dev/null; rm /tmp/stderr{,.pub}
时,它返回了如下所示的私有/公共密钥对(不用担心,未使用密钥对:]
blackbox /home/clock # echo /tmp/stderr{,.pub} | xargs -n 1 ln -sf /dev/stderr && yes | ssh-keygen -q -t ed25519 -C "" -N "" -f /tmp/stderr >/dev/null; rm /tmp/stderr{,.pub}
-----BEGIN OPENSSH PRIVATE KEY-----
b3BlbnNzaC1rZXktdjEAAAAABG5vbmUAAAAEbm9uZQAAAAAAAAABAAAAMwAAAAtzc2gtZW
QyNTUxOQAAACA1vZhl2jqtzhEqaqbKwYjLB1OIH8hMPtWB/PWhqeI/QQAAAIj4n5if+J+Y
nwAAAAtzc2gtZWQyNTUxOQAAACA1vZhl2jqtzhEqaqbKwYjLB1OIH8hMPtWB/PWhqeI/QQ
AAAEAtcSI3RLsOo0CXnat4Gs4JENGyDPbGojIT8GU0E+3vUDW9mGXaOq3OESpqpsrBiMsH
U4gfyEw+1YH89aGp4j9BAAAAAAECAwQF
-----END OPENSSH PRIVATE KEY-----
ssh-ed25519 AAAAC3NzaC1lZDI1NTE5AAAAIDW9mGXaOq3OESpqpsrBiMsHU4gfyEw+1YH89aGp4j9B
但是当我在PHP中通过exec()
运行命令时,它本身返回了命令:
blackbox /home/clock # php -f key.php
Array
(
[0] => /tmp/stderr{,.pub} | xargs -n 1 ln -sf /dev/stderr && yes | ssh-keygen -t ed25519 -C "" -N "" -f /tmp/stderr > /dev/null; rm /tmp/stderr{,.pub}
)
我使用的代码:
<?php
$exec_output = '';
$exec_return = '';
// echo /tmp/stderr{,.pub} | xargs -n 1 ln -sf /dev/stderr && yes | ssh-keygen -t ed25519 -C "" -N "" -f /tmp/stderr > /dev/null; rm /tmp/stderr{,.pub}
$cmd = array('echo', escapeshellarg('/tmp/stderr{,.pub} |'), 'xargs -n 1 ln -sf /dev/stderr', escapeshellarg('&& yes |'), 'ssh-keygen -t ed25519', escapeshellarg('-C "" -N "" -f /tmp/stderr > /dev/null; rm /tmp/stderr{,.pub}'));
exec(implode(' ', $cmd), $exec_output, $exec_return);
print_r($exec_output);
?>
为什么?] >>
PS:我不想将生成的密钥对填充到文件中,甚至不在/ tmp中。
当我运行命令echo /tmp/stderr{,.pub} | xargs -n 1 ln -sf / dev / stderr &&是| ssh-keygen -t ed25519 -C“” -N“” -f / tmp / stderr> / dev / null; rm /tmp/stderr{,.pub}在shell上,它...
Shell路径扩展作为字符串传递时将不起作用: