用 C 语言查找两个数组的交集 b 的程序...我的数组没有占用我想输入的 ele 的 n.o，

Question

#include<stdio.h>;
int main(){
int a[100],b[100],n,m,i,j;
printf("enter n.o of ele to enter in A  \n");
scanf("%d",&n);
printf("enter elements into array A:\n");
for(i=0;i<n;i++){
    scanf("%d \n",&a[i]);
    
}
printf("enter n.o of ele to enter in B  \n");
scanf("%d ",&m);
printf("enter elements into array B:\n");
for(j=0;j<m;j++){
    scanf("%d \n",&b[j]);
    
}
printf("common ele are :\n");
for(i=0;i<n;i++){
    
    for(j=0;j<m;j++){
        if(a[i]==b[j]){
            printf("%d \n",a[i]);
            break;
        }
    }
}

}

这是我的程序

我希望它能给出数组中的公共元素，但它没有占用我想要的元素数量 如果我想在数组中输入 4 个元素，它需要超过 4

Answer 1

在测试代码时，主要问题在于“scanf”函数调用中使用的格式。例如，以下 scanf 调用因格式中包含换行符而变得混乱。

scanf("%d \n",&a[i]);

仔细阅读了您的代码，以下是一个重构版本，对 scanf 函数进行了一些清理，并添加了一些额外的输出文本，使程序更加用户友好。

#include<stdio.h>

int main()
{
    int a[100],b[100],n,m,i,j;
    printf("enter n.o of ele to enter in A  \n");
    scanf("%d",&n);
    printf("enter elements into array A:\n");
    for(i=0; i<n; i++)
    {
        printf("Element: ");    /* To provide some user friendly prompting */
        scanf("%d", &a[i]);     /* Clean up of the scanf formatting        */
    }

    printf("Enter n.o of ele to enter in B  \n");
    scanf("%d",&m);             /* Clean up of the scanf formatting        */
    printf("Enter elements into array B:\n");

    for(j=0; j<m; j++)
    {
        printf("Element: ");    /* To provide some user friendly prompting */
        scanf("%d", &b[j]);     /* Clean up of the scanf formatting        */
    }
    printf("Common ele are :\n");
    for(i=0; i<n; i++)
    {

        for(j=0; j<m; j++)
        {
            if(a[i]==b[j])
            {
                printf("%d \n",a[i]);
                //break;        /* Should not want this if all matches are to be printed */
            }
        }
    }
    return 0;
}

请注意，换行符和空格填充等项目已被删除。通过这些重构，下面是对重构代码的测试。

@Vera:~/C_Programs/Console/Intersect/bin/Release$ ./Intersect 
enter n.o of ele to enter in A  
3
enter elements into array A:
Element: 44
Element: 88
Element: 77
Enter n.o of ele to enter in B  
3
Enter elements into array B:
Element: 77
Element: 55
Element: 88
Common ele are :
88 
77 

你可能想对 scanf 函数做更多的研究，但试试这个重构代码，看看它是否符合你项目的精神。