如何使用 MySQL MATCH AGAINST IN BOOLEAN MODE 返回关键字字符串中至少 1 个匹配关键字的结果？

Question

我有一个根据在搜索框中输入的关键字搜索数据库条目的查询。

// function to get search keywords from url
$q = furl($_GET['q']);

$sExp = preg_split('/\s+/',$q); 
$secure_keywords = array(); 
foreach ($sExp as $key=>$keyword){
    if (strlen($keyword) >= 3){ 
    // cut off words that are less than 3 chars
    $secure_keywords[] = $keyword;
    }
}
$kwords = count($secure_keywords); 
foreach ($secure_keywords as $key=>$keyword) 
{ 
// function to prevent sql injection
$keyword = sql_proof($keyword); 

$query="SELECT * FROM listings WHERE MATCH (meta_keywords) AGAINST ('$keyword' IN BOOLEAN MODE) ORDER BY id"; 
} 

当使用 2 个或更多单词时，如果至少有 1 个单词拼写错误，则查询将不会返回任何结果（即使输入的关键字中的其余单词确实存在结果）。例如，我输入单词“good”，我至少得到 1 个结果，但如果我使用“good point”，查询不会返回任何结果，因此它完全忽略单词“good”的匹配结果。 如果输入的关键字中至少有 1 个匹配单词，是否有办法让查询匹配结果？谢谢

Answer 1

不要使用“布尔模式”尝试

SELECT * FROM articles WHERE MATCH (title, body) AGAINST ('database test')

即使数据库后面没有“test”之类的单词，它也会返回结果

SELECT * FROM tablename WHERE MATCH (col1, col2) AGAINST ('string to be searched')

Answer 2

查看以下解决方案，了解将结果与所使用的任何关键字进行匹配的方法。另请查看文档以获取有关运算符和布尔 fst 的更多信息http://dev.mysql.com/doc/refman/5.1/en/fulltext-boolean.html

// function to get search keywords from url
$q = furl($_GET['q']);

$sExp = preg_split('/\s+/',$q); 
$secure_keywords = array(); 
foreach ($sExp as $key=>$keyword){
    if (strlen($keyword) >= 3){ 
    // cut off words that are less than 3 chars
    $secure_keywords[] = $keyword;
    }
}
$kwords = count($secure_keywords); 

//init empty keywords array
$keywords = array();

//secure all keywords
$keywords = array_map(function($item){ return sql_proof($item); }, $secure_keywords); 

//implode the words with a space between
$keywords = implode(" ",$keywords);

//just one query with match against ANY of the words from initial keyword array
$query="SELECT * FROM listings WHERE MATCH (meta_keywords) AGAINST ('$keywords' IN BOOLEAN MODE) ORDER BY id";