如何使用错误响应其余模板处理200个状态代码?

问题描述 投票:0回答:1

我想通过错误响应处理200

final ResponseEntity<ResponseType> responseEntity = restTemplate.postForEntity(url, requestEntity, ResponseType.class);

在这里我直接在rest模板中使用响应模型对象,下面是我的catch块

catch (final RestClientException | HttpMessageConversionException ex) {
                throw new CustomException(message, ex);
            }

在这里我添加了HttpMessageConversionException,因为我得到200的错误响应,并且在将其转换为rest模板中的成功响应类型类时抛出该错误,因为在我的成功响应类构造函数中具有字段验证。

下面是我在rest模板中使用的响应类

@JsonDeserialize(builder = ResponseType.Builder.class)
@JacksonXmlRootElement(localName = "Test")
public class ResponseType {

    private final String details;

    private ResponseType(final Builder builder) {
        this.details = OptionalCheck.checkPresent(builder.details, "details");
    }

    public static Builder builder() {
        return new Builder();
    }

    //getter

    public static final class Builder {
        private Optional<String> details = Optional.empty();

        @JacksonXmlProperty(localName = "details")
        public Builder withDetails(final String theDetails) {
            this.details = Optional.ofNullable(theDetails);
            return this;
        }


        public ResponseType build() {
            return new ResponseType(this);
        }
    }
}

下面是堆栈跟踪

org.springframework.http.converter.HttpMessageConversionException: Type definition error: [simple type, class com.test.ResponseType$Builder]; nested exception is com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `com.test.ResponseType$Builder`, problem: details must be present.
 at [Source: (ByteArrayInputStream); line: 5, column: 1]
    at org.springframework.http.converter.json.AbstractJackson2HttpMessageConverter.readJavaType(AbstractJackson2HttpMessageConverter.java:242)
    at org.springframework.http.converter.json.AbstractJackson2HttpMessageConverter.read(AbstractJackson2HttpMessageConverter.java:227)
    at org.springframework.web.client.HttpMessageConverterExtractor.extractData(HttpMessageConverterExtractor.java:102)
    at org.springframework.web.client.RestTemplate$ResponseEntityResponseExtractor.extractData(RestTemplate.java:994)
    at org.springframework.web.client.RestTemplate$ResponseEntityResponseExtractor.extractData(RestTemplate.java:977)
    at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:737)
    at org.springframework.web.client.RestTemplate.execute(RestTemplate.java:670)
    at org.springframework.web.client.RestTemplate.postForEntity(RestTemplate.java:445)

    Caused by: java.lang.IllegalArgumentException: details must be present.
    at com.test.OptionalCheck.lambda$checkPresent$0(OptionalCheck.java:46)
    at java.base/java.util.Optional.orElseThrow(Optional.java:408)

还有其他处理方法吗?

java spring spring-boot resttemplate spring-rest
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