我需要弄清楚两个时区之间的小时差异,当前面的时区移动到第二天时,我遇到了一些问题。
例:
//Let's say it is 11pm 23:00 in LA
$local_tz = new DateTimeZone('America/Los_Angeles');
$local = new DateTime('now', $local_tz);
$local_hour = $local->format('H');
//NY is 3 hours ahead, so it is 2am, 02:00
$user_tz = new DateTimeZone('America/New_York');
$user = new DateTime('now', $user_tz);
$user_hour = $user->format('H');
按照这个问题中的例子(Calculate hours between dates in different time zones)我得到一个不正确的结果:
$diff = $user_tz->getOffset($local);
error_log('$diff '.gmdate("H:i:s", $diff)); //outputs 20:00:00
如果是在洛杉矶的下午4点,那么在纽约的晚上7点那么很容易:
$time_diff = ($user_h - $local_h); //$time_diff = 3;
但是当纽约搬到第二天时,我又得到了不正确的结果:
$time_diff = ($user_h - $local_h); //$time_diff = -21;
那么我怎样才能解释另一个已经搬到新的一天的时区呢?
您可以使用时区偏移在两个时区之间获得小时差异,请尝试以下代码:
$local_tz = new DateTimeZone('America/Los_Angeles');
$local = new DateTime('now', $local_tz);
//NY is 3 hours ahead, so it is 2am, 02:00
$user_tz = new DateTimeZone('America/New_York');
$user = new DateTime('now', $user_tz);
$local_offset = $local->getOffset() / 3600;
$user_offset = $user->getOffset() / 3600;
$diff = $user_offset - $local_offset;
print_r($diff); //outputs 3
我设法找到了一个解决方案,DateInterval类不断为我抛出21,虽然当我输出对象时我可以看到小时为3。
由于DateTime与epoch进行比较并忽略时区,因此我必须为两个时间创建一个新的DateTime,然后运行比较。
//Let's say it is 11pm 23:00 in LA
$local_tz = new DateTimeZone('America/Los_Angeles');
$local = new DateTime('now', $local_tz);
//NY is 3 hours ahead, so it is 2am, 02:00
$user_tz = new DateTimeZone('America/New_York');
$user = new DateTime('now', $user_tz);
$usersTime = new DateTime($user->format('Y-m-d H:i:s'));
$localsTime = new DateTime($local->format('Y-m-d H:i:s'));
$interval = $usersTime->diff($localsTime);
print_r($interval->h); //outputs 3
使用$user->modify("-4 hours"); $local->modify("-4 hours");
运行测试返回3.(其中一个在前一天的午夜之前放置)