如何在HttpURLConnection中发送PUT,DELETE HTTP请求?

问题描述 投票:122回答:9

我想知道是否可以通过java.net.HttpURLConnection将PUT,DELETE请求(实际上)发送到基于HTTP的URL。

我已经阅读了很多文章,描述了如何发送GET,POST,TRACE,OPTIONS请求,但我仍然没有找到任何成功执行PUT和DELETE请求的示例代码。

java httpurlconnection put http-delete
9个回答
166
投票

要执行HTTP PUT:

URL url = new URL("http://www.example.com/resource");
HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();
httpCon.setDoOutput(true);
httpCon.setRequestMethod("PUT");
OutputStreamWriter out = new OutputStreamWriter(
    httpCon.getOutputStream());
out.write("Resource content");
out.close();
httpCon.getInputStream();

要执行HTTP DELETE:

URL url = new URL("http://www.example.com/resource");
HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();
httpCon.setDoOutput(true);
httpCon.setRequestProperty(
    "Content-Type", "application/x-www-form-urlencoded" );
httpCon.setRequestMethod("DELETE");
httpCon.connect();

22
投票

这是它对我有用的方式:

HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("DELETE");
int responseCode = connection.getResponseCode();

10
投票
public  HttpURLConnection getHttpConnection(String url, String type){
        URL uri = null;
        HttpURLConnection con = null;
        try{
            uri = new URL(url);
            con = (HttpURLConnection) uri.openConnection();
            con.setRequestMethod(type); //type: POST, PUT, DELETE, GET
            con.setDoOutput(true);
            con.setDoInput(true);
            con.setConnectTimeout(60000); //60 secs
            con.setReadTimeout(60000); //60 secs
            con.setRequestProperty("Accept-Encoding", "Your Encoding");
            con.setRequestProperty("Content-Type", "Your Encoding");
        }catch(Exception e){
            logger.info( "connection i/o failed" );
        }
        return con;
}

然后在你的代码中:

public void yourmethod(String url, String type, String reqbody){
    HttpURLConnection con = null;
    String result = null;
    try {
        con = conUtil.getHttpConnection( url , type);
    //you can add any request body here if you want to post
         if( reqbody != null){  
                con.setDoInput(true);
                con.setDoOutput(true);
                DataOutputStream out = new  DataOutputStream(con.getOutputStream());
                out.writeBytes(reqbody);
                out.flush();
                out.close();
            }
        con.connect();
        BufferedReader in = new BufferedReader(new InputStreamReader(con.getInputStream()));
        String temp = null;
        StringBuilder sb = new StringBuilder();
        while((temp = in.readLine()) != null){
            sb.append(temp).append(" ");
        }
        result = sb.toString();
        in.close();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
        logger.error(e.getMessage());
    }
//result is the response you get from the remote side
}

8
投票

我同意@adietisheim和其他建议HttpClient的人。

我花了很多时间尝试使用HttpURLConnection进行简单的休息服务,并且它没有说服我,之后我尝试使用HttpClient,它真的更容易,可以理解和更好。

进行put http调用的代码示例如下:

DefaultHttpClient httpClient = new DefaultHttpClient();

HttpPut putRequest = new HttpPut(URI);

StringEntity input = new StringEntity(XML);
input.setContentType(CONTENT_TYPE);

putRequest.setEntity(input);
HttpResponse response = httpClient.execute(putRequest);

3
投票

UrlConnection是一个难以使用的API。 HttpClient是迄今为止更好的API,它将使您免于浪费时间搜索如何实现某些事情,例如stackoverflow问题完全说明。我在几个REST客户端中使用了jdk HttpUrlConnection之后编写了这个。此外,当谈到可伸缩性功能(如线程池,连接池等)时,HttpClient非常出色


3
投票

要正确执行HTML中的PUT,您必须使用try / catch包围它:

try {
    url = new URL("http://www.example.com/resource");
    HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();
    httpCon.setDoOutput(true);
    httpCon.setRequestMethod("PUT");
    OutputStreamWriter out = new OutputStreamWriter(
        httpCon.getOutputStream());
    out.write("Resource content");
    out.close();
    httpCon.getInputStream();
} catch (MalformedURLException e) {
    e.printStackTrace();
} catch (ProtocolException e) {
    e.printStackTrace();
} catch (IOException e) {
    e.printStackTrace();
}

0
投票

我会推荐Apache HTTPClient。


0
投票

即使是休息模板也可以选择:

String payload = "<?xml version=\"1.0\" encoding=\"UTF-8\"?<CourierServiceabilityRequest>....";
    RestTemplate rest = new RestTemplate();

    HttpHeaders headers = new HttpHeaders();
    headers.add("Content-Type", "application/xml");
    headers.add("Accept", "*/*");
    HttpEntity<String> requestEntity = new HttpEntity<String>(payload, headers);
    ResponseEntity<String> responseEntity =
            rest.exchange(url, HttpMethod.PUT, requestEntity, String.class);

     responseEntity.getBody().toString();

0
投票

有一个简单的删除和放置请求的方法,你可以通过在你的帖子请求中添加一个“_method”参数并为其值写“PUT”或“DELETE”来做到这一点!

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