通过mixins处理带有自定义slugs的重复对象

问题描述 投票:0回答:1

我们有一个django应用程序,包含两个对象,城市和事件。我们的常见网址模式是:

app.com/city/name-of-city/event/name-of-event,其中name-of-cityname-of-event是slug。例如:

class City(models.Model):
      name = models.CharField(max_length=100, unique=True)
      slug = AutoSlugField(populate_from='name', always_update=True, unique=True, sep='-', max_length=255)
      ...

事件在Event模型中以相同的方式获取它们的slug:

slug = AutoSlugField(populate_from='name', always_update=True, unique_with='city', sep='-', max_length=255)

我难以解决的问题是如何处理同一个城市有多个具有相同名称的事件的实例。

迷信是.朋友

class CityMixin(object):
    city_slug_url_kwarg = 'slug'
    city = None

    def fetch_city(self, request, *args, **kwargs):
        if not self.city:
            self.city = get_object_or_404(
                City, slug=kwargs.get(self.city_slug_url_kwarg))
        return self.city

    def get_context_data(self, **kwargs):
        kwargs.setdefault('city', self.city)
        return super(CityMixin, self).get_context_data(**kwargs)

    def dispatch(self, request, *args, **kwargs):
        """
        Sets 'city' within the view
        """
        self.city = self.fetch_city(request, *args, **kwargs)
        return super(CityMixin, self).dispatch(request, *args, **kwargs)


class EventMixin(CityMixin):
    city_slug_url_kwarg = 'city_slug'
    event_slug_url_kwarg = 'slug'
    event = None

    def fetch_event(self, request, *args, **kwargs):

        if not self.event:
            event = get_list_or_404(
                Event, slug=kwargs.get(self.event_slug_url_kwarg))

        return self.event

    def dispatch(self, request, *args, **kwargs):
        """
        Sets 'city' and 'event' within the view
        """
        user = request.user
        self.city = self.fetch_city(request, *args, **kwargs)
        self.event = self.fetch_event(request, *args, **kwargs)
        if self.event.city != self.city:
            raise Http404

        return super(EventMixin, self).dispatch(request, *args, **kwargs)

如果我要求事件:

event = get_object_or_404(Event, slug=kwargs.get(self.event_slug_url_kwarg))

如果存在多个具有相同名称的事件,它将抛出一个错误(MultipleObjectsReturned)。

如果我要求事件:

event = get_list_or_404(Event, slug=kwargs.get(self.event_slug_url_kwarg))

并且有相同的事件,应用程序不知道列表中的哪个obj或索引是正确的obj。

有没有一种方法可以确保请求正确的obj,也可以处理重复的事件名称案例?

谢谢

django django-models django-views django-urls slug
1个回答
1
投票

每个城市的slu will总是唯一的,因为你已经设定了unique_with属性。但是你没有在查询中使用这个城市,所以你将获得所有城市的活动 - 可以使用相同的slug。您需要在查找中使用城市:

event = get_list_or_404(
    Event,
    slug=kwargs.get(self.event_slug_url_kwarg),
    city__slug=kwargs.get(self.city_slug_url_kwarg)
)
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