我正在尝试创建一个新线程gpsthread
,该线程应在后台运行并存储值。
class gpsthread: public QThread{
Q_OBJECT
private:nrega_status_t status2;
public:
explicit gpsthread(QObject *parent = 0):QThread(parent) {
// QTimer *t = new QTimer(this);
// connect(t, SIGNAL(timeout()), this, SLOT(processgps()));
// t->start(10000);
}
void run(){
qDebug()<<"inside gps thread\n";
QTimer *t = new QTimer(this);
connect(t, SIGNAL(timeout()), this, SLOT(processgps()));
t->start(10000);
}
public slots:void processgps(){
int status2;
status2=gps_management();
}
};
我的主要课程是快速浏览。
int main(int argc, char *argv[])
{
QString file = "qml/main.qml";
QApplication app(argc, argv);
TranslationTest myObj;
QuickView view;
subthread object;
gpsthread obj;
gprsthread gprs;
view.rootContext()->setContextProperty("rootItem", (QObject *)&myObj);
obj.start();
//from subthread
QObject::connect(&object, SIGNAL(batterytoqml(QVariant,QVariant)),item, SLOT(frombattery(QVariant,QVariant)));
QObject::connect(&gprs, SIGNAL(gprstoqml(QVariant)),item, SLOT(fromgprs(QVariant)));
return app.exec();
}
我也尝试过这个]
class gpsthread: public QThread{ Q_OBJECT private:nrega_status_t status2; public:QTimer* t; explicit gpsthread(QObject *parent = 0):QThread(parent) { // QTimer *t = new QTimer(this); // connect(t, SIGNAL(timeout()), this, SLOT(processgps())); // t->start(10000); } void run(){ qDebug()<<"inside gps thread\n"; t = new QTimer(this); connect(t, SIGNAL(timeout()), this, SLOT(processgps())); t->start(10000); exec(); } public slots:void processgps(){ int status2; status2=gps_management(); } };
但是给出错误的说法
QObject: Cannot create children for a parent that is in a different thread
如果我在构造函数中创建对象,那么它也会给出相同的错误,因为该对象将在主线程中创建。如何解决呢?
我正在尝试创建一个新线程gpsthread,该线程应在后台运行并存储值。 gpsthread类:公共QThread {Q_OBJECT私有:nrega_status_t status2; public:显式...
不推荐从QThread继承。 QThread是运行事件循环的完整类,通常这是您需要的。 documentation建议使用从QObject继承并在插槽中工作的工作程序对象。工人被移到QThread中。发送连接的信号后,插槽将在正确的线程中运行。
QObject: Cannot create children for a parent that is in a different thready