JPA - 一对多合并问题

Question

当我尝试合并一个实体时，我正面临下一个问题。

我有一个课程菜单（一对多） - >类别（一对多） - >商品关联。

如果我首先坚持使用空的列表类别和商品的菜单，菜单将被正确保留。

现在，如果我将当前保存菜单与一个类别合并并清空商品列表，则类别保存正常，即使我将新商品添加到空白商品列表中也可以保留。

现在，如果我在商品列表中添加第二个商品，我会遇到此错误：

菜单[menuId = 1，menu_name = dsad，menu_description = null，categories = [Category [category_id = 1，categoryName = a，goods = [GoodsImp [id = 1，brand = asd，createdDate = Mon Jan 22 18:26:35 ART 2018]，price = 3.0，description = asd，type = product]]，GoodsImp [id = null，brand = dsad，createdDate = null]，price = 33333.0，description = sd，type = product]]]]，Category [category_id = 2，categoryName = b，goods = []]]，business = 2]

-------------- Hibernate：

/* load models.menu.Menu */ select
    menu0_.MENU_ID as MENU_ID1_7_1_,
    menu0_.BUSINESS_ID as BUSINESS2_7_1_,
    menu0_.MENU_DESCRIPTION as MENU_DES3_7_1_,
    menu0_.MENU_NAME as MENU_NAM4_7_1_,
    categories1_.Menu_MENU_ID as Menu_MEN1_8_3_,
    category2_.CATEGORY_ID as categori2_8_3_,
    category2_.CATEGORY_ID as CATEGORY1_2_0_,
    category2_.CATEGORY_NAME as CATEGORY2_2_0_
from
    MENUES menu0_
left outer join
    MENUES_CATEGORIES categories1_
        on menu0_.MENU_ID=categories1_.Menu_MENU_ID
left outer join
    Categories category2_
        on categories1_.categories_CATEGORY_ID=category2_.CATEGORY_ID
where
    menu0_.MENU_ID=? Hibernate:
/* load models.menu.Product */ select
    product0_.GOODS_ID as GOODS_ID2_6_0_,
    product0_.GOODS_BRAND as GOODS_BR3_6_0_,
    product0_.GOODS_CREATED as GOODS_CR4_6_0_,
    product0_.GOODS_DESCRIPTION as GOODS_DE5_6_0_,
    product0_.GOODS_IMAGE as GOODS_IM6_6_0_,
    product0_.GOODS_PRICE as GOODS_PR7_6_0_
from
    GOODS product0_
where
    product0_.GOODS_ID=?
    and product0_.DTYPE='PRODUCT'

休眠：

/* insert models.menu.Product
    */ insert
    into
        GOODS
        (GOODS_BRAND, GOODS_CREATED, GOODS_DESCRIPTION, GOODS_IMAGE, GOODS_PRICE, DTYPE)
    values
        (?, ?, ?, ?, ?, 'PRODUCT') Hibernate:
select
    goods0_.GOODS_ID as GOODS_ID2_6_0_,
    goods0_.GOODS_ID as GOODS_ID2_6_1_,
    goods0_.GOODS_BRAND as GOODS_BR3_6_1_,
    goods0_.GOODS_CREATED as GOODS_CR4_6_1_,
    goods0_.GOODS_DESCRIPTION as GOODS_DE5_6_1_,
    goods0_.GOODS_IMAGE as GOODS_IM6_6_1_,
    goods0_.GOODS_PRICE as GOODS_PR7_6_1_,
    goods0_.GOODS_PRICE_TYPE as GOODS_PR8_6_1_,
    goods0_.DTYPE as DTYPE1_6_1_
from
    GOODS goods0_
where
    goods0_.GOODS_ID=? Hibernate:
select
    goods0_.GOODS_ID as GOODS_ID2_6_0_,
    goods0_.GOODS_ID as GOODS_ID2_6_1_,
    goods0_.GOODS_BRAND as GOODS_BR3_6_1_,
    goods0_.GOODS_CREATED as GOODS_CR4_6_1_,
    goods0_.GOODS_DESCRIPTION as GOODS_DE5_6_1_,
    goods0_.GOODS_IMAGE as GOODS_IM6_6_1_,
    goods0_.GOODS_PRICE as GOODS_PR7_6_1_,
    goods0_.GOODS_PRICE_TYPE as GOODS_PR8_6_1_,
    goods0_.DTYPE as DTYPE1_6_1_
from
    GOODS goods0_
where
    goods0_.GOODS_ID=? Hibernate:



   /* update  models.menu.Product */ update
        GOODS
    set
        GOODS_BRAND=?,
        GOODS_CREATED=?,
        GOODS_DESCRIPTION=?,
        GOODS_IMAGE=?,
        GOODS_PRICE=?
    where
        GOODS_ID=? Hibernate:
/* create one-to-many row models.menu.Category.goods */ update
    GOODS
set
    GOODS_ID=?
where
    GOODS_ID=? [warn] o.h.e.j.s.SqlExceptionHelper - SQL Error: 1062, SQLState: 23000 [error] o.h.e.j.s.SqlExceptionHelper - Duplicate

键'PRIMARY'[错误]应用程序的条目'1' -

！ @ 76lfn933p - 内部服务器错误，（PUT）[/ menu] - >

play.api.http.HttpErrorHandlerExceptions $$ anon $ 1：执行异常[[PersistenceException：org.hibernate.exception.ConstraintViolationException：无法执行语句]] at play.api.http.HttpErrorHandlerExceptions $ .throwableToUsefulException（HttpErrorHandler.scala：255） at play.api.http.DefaultHttpErrorHandler.onServerError（HttpErrorHandler.scala：182）at play.filters.cors.AbstractCORSPolicy $$ anonfun $ 1.applyOrElse（AbstractCORSPolicy.scala：155）at play.filters.cors.AbstractCORSPolicy $$ anonfun $ 1 .applyOrElse（AbstractCORSPolicy.scala：153）at scala.concurrent.Future。$ anonfun $ recoverWith $ 1（Future.scala：412）at scala.concurrent.impl.Promise。$ anonfun $ transformWith $ 1（Promise.scala：37）at at scala.concurrent.impl.CallbackRunnable.run（Promise.scala：60）at play.api.libs.streams.Execution $ trampoline $ .execute（Execution.scala：70）at scala.concurrent.impl.CallbackRunnable.executeWithValue（Promise .scala：68）at scala.concurrent.impl.Promise $ DefaultPromise。$ anonfun $ tryComplete $ 1（Promise.scala：284）Caus编辑：javax.persistence.PersistenceException：org.hibernate.exception.ConstraintViolationException：无法在org.hibernate.internal.ExceptionConverterImpl.convert（ExceptionConverterImpl）的org.hibernate.internal.ExceptionConverterImpl.convert（ExceptionConverterImpl.java:149）中执行语句.java：157）在org.hibernate.internal.SessionImpl.flush上的org.hibernate.internal.ExceptionConverterImpl.convert（ExceptionConverterImpl.java:164）org.hibernate.internal.SessionImpl.doFlush（SessionImpl.java:1443） SessionImpl.java:1423）at repository.dPAMenuesRepository.lambda $ updateMenu $ 2（JPAMenuesRepository.java:46）at play.db.jpa.DefaultJPAApi.lambda $ withTransaction $ 3（DefaultJPAApi.java:197）at play.db.jpa.DefaultJPAApi .withTransaction（DefaultJPAApi.java:138）at play.db.jpa.DefaultJPAApi.withTransaction（DefaultJPAApi.java:196）at play.db.jpa.DefaultJPAApi.withTransaction（DefaultJPAApi.java:169）引起：org.hibernate。 exception.ConstraintViolationException：无法在o处执行语句位于org.hibernate.engine.jdbc.spi.SqlExceptionHelper的org.hibernate.exception.internal.StandardSQLExceptionConverter.convert（StandardSQLExceptionConverter.java:42）中的rg.hibernate.exception.internal.SQLExceptionTypeDelegate.convert（SQLExceptionTypeDelegate.java:59）。转换（sqlExceptionHelper.java:111）atg.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert（SqlExceptionHelper.java:97）org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.executeUpdate（ResultSetReturnImpl.java:178）在org.hibernate.perst.Bot中的org.hibernate.engz.batch.internal.NonBatchingBatch.addToBatch（NonBatchingBatch.java:45）org.hibernate.persister.colsert.AbstractCollectionPersister.insertRows（AbstractCollectionPersister.java:1567） .OneToManyPersister.insertRows（OneToManyPersister.java:193）org.hibernate.action.CollectionUpdateAction.exe执行（CollectionUpdateAction.java:85）org.hibernate.engine.spi.ActionQueue.executeActions（ActionQueue.java:589）通过：com.mysql.jdbc .exceptions.jdbc4.MySQLIntegrityConstraintViolationException：sun.reflect.DelegatingConstructorAccessorImpl.newInstance（在sun.reflect.NativeConstructorAccessorImpl.newInstance（未知来源））sun.reflect.NativeConstructorAccessorImpl.newInstance0（本地方法）中的键'PRIMARY'复制条目'1'源自com.mysql.jdbc.Util.handleNewInstance（Util.java:425）的java.lang.reflect.Constructor.newInstance（Unknown Source）at com.mysql.jdbc.Util.getInstance（Util.java:408） ）com.mysql.jdbc.SQLError.createSQLException（SQLError.java:936）com.mysql.jdbc.MysqlIO.checkErrorPacket（MysqlIO.java:3973）com.mysql.jdbc.MysqlIO.checkErrorPacket（MysqlIO.java： 3909）在com.mysql.jdbc.MysqlIO.sendCommand（MysqlIO.java:2527）

Answer 1

我可以解决它。

问题是，One to Many的关系有@JoinColumn而不是@JoinTable。你编写几个小时的问题就是这个问题，你只是看不出明显的问题。

谢谢大家。