当我用变量替换硬编码值时，Python SQL查询返回“ ORA-00936：缺少表达式”>

Question

我有一个充满信息的数据库，我正在尝试编写一个python脚本，该脚本将提取一些数据并将其组织成报告。这是我到目前为止的内容：

import cx_Oracle
import pandas as pd

conn = cx_Oracle.connect('REDACTED')
cursor = conn.cursor()

# Currently hard-coded to return single known motor number
cursor.execute('SELECT MOTORID FROM MOTORS WHERE SERIALNUM=804')
# Returns [(11)]
lMotorID = cursor.fetchall()

# Query Assessments for list of how long the motor had run when assessment was taken
cursor.execute("SELECT DISTINCT RUNHOURS FROM ASSESSMENTS WHERE MOTORID = %s \
               ORDER BY RUNHOURS" % lMotorID[0])
# Returns [(0), (0.91), (8), (25), ...]
lHours = cursor.fetchall()

# Query for number of installed sensors by senor type
cursor.execute("SELECT SENSTYP, COUNT(STATUS) FROM HEALTH LEFT JOIN INSTRUMENTATION \
               ON HEALTH.INSTROID = INSTRUMENTATION.INSTROID LEFT JOIN ASSESSMENTS \
               ON HEALTH.ASSESSID = ASSESSMENTS.ASSESSID WHERE ASSESSMENTS.ASSESSID \
               IN (SELECT ASSESSID FROM ASSESSMENTS WHERE MOTORID = 11 AND RUNHOURS = %s) \
               GROUP BY SENSTYP ORDER BY SENSTYP" % lHours[2])
# Returns a 2-column dataframe with sensor type in column 0 and the total in column 1
dfTotal = pd.DataFrame(cursor.fetchall())
因为我希望此方法适用于任何电动机，所以我想用一个变量替换硬编码的MOTORID = 11。我试着用这个替换最后一个查询：

cursor.execute("SELECT SENSTYP, COUNT(STATUS) FROM HEALTH LEFT JOIN INSTRUMENTATION \
               ON HEALTH.INSTROID = INSTRUMENTATION.INSTROID LEFT JOIN ASSESSMENTS \
               ON HEALTH.ASSESSID = ASSESSMENTS.ASSESSID WHERE ASSESSMENTS.ASSESSID \
               IN (SELECT ASSESSID FROM ASSESSMENTS WHERE MOTORID = %s AND RUNHOURS = %s) \
               GROUP BY SENSTYP ORDER BY SENSTYP" % (lMotorID[0], lHours[2])) 
dfTotal = pd.DataFrame(cursor.fetchall())
这就是我收到ORA-00936错误的时间。我不明白为什么查询要用硬编码的值完成，但是不知道用一个变量替换该值（在上一个查询中有效）。预先感谢。

我有一个充满信息的数据库，我正在尝试编写一个python脚本，该脚本将提取一些数据并将其组织成报告。到目前为止，这是我所拥有的：import cx_Oracle import pandas ...

Answer 1

需要修复cursor.execute的语法，例如