如何获取复杂数组中列表项的第二低值

Question

我目前在我的文件中使用此解决方案，以从 api 调用返回给定路线的最快巴士出发前的分钟数，然后显示它：

soonestDepartureTimeUnix = min(item["departure_time"] for item in tsl105513Route2["itineraries"][0]["schedule_items"])
minutes = int((soonestDepartureTimeUnix - (time.time()))/60)

但是，当分钟值 = 0 时，这对于路人来说就没那么有用了。

就上下文而言，API 调用的响应如下所示：

{
    "route_departures": [
        {
            "global_route_id": "TSL:105513",
            "itineraries": [
                {
                    "branch_code": "",
                    "direction_headsign": "*******",
                    "direction_id": 1,
                    "headsign": "******",
                    "merged_headsign": "******",
                    "schedule_items": [
                        {
                            "departure_time": 1713461520,
                            "is_cancelled": false,
                            "is_real_time": false,
                            "rt_trip_id": "13811798",
                            "scheduled_departure_time": 1713461520,
                            "trip_search_key": "TSL:45069396:369:5:15",
                            "wheelchair_accessible": 1
                        },
                        {
                            "departure_time": 1713463320,
                            "is_cancelled": false,
                            "is_real_time": false,
                            "rt_trip_id": "13811799",
                            "scheduled_departure_time": 1713463320,
                            "trip_search_key": "TSL:45069396:369:5:16",
                            "wheelchair_accessible": 1
                        },
                        {
                            "departure_time": 1713465120,
                            "is_cancelled": false,
                            "is_real_time": false,
                            "rt_trip_id": "13811800",
                            "scheduled_departure_time": 1713465120,
                            "trip_search_key": "TSL:45069396:369:5:17",
                            "wheelchair_accessible": 1
                        }
                    ]
                }
            ],
            "mode_name": "Bus",
            "real_time_route_id": "30048",
            "route_color": "2a61a0",
            "route_long_name": "******",
            "route_network_id": "TransLink|Vancouver",
            "route_network_name": "TransLink",
            "route_short_name": "**8",
            "route_text_color": "ffffff",
            "route_type": 3,
            "sorting_key": "***",
            "tts_long_name": "*****",
            "tts_short_name": "*** "
        }
    ]
}

我尝试了多种解决方案，包括跳转到数组中的下一项：

if minutes < 1:
            soonestDepartureTimeUnix = (item["departure_time"] for item in tsl105513Route2["itineraries"][1]["schedule_items"])
            minutes = int((soonestDepartureTimeUnix - (time.time()))/60)

但这返回了“列表项超出范围”错误。

我也尝试过这个：

if minutes < 1:
            soonestDepartureTimeUnix = (item["departure_time"] for item in tsl105513Route2["itineraries"][0]["schedule_items"][1])
            minutes = int((soonestDepartureTimeUnix - (time.time()))/60)

但是我收到一个错误，说不能在生成器和浮点数之间进行减法运算。

最后我尝试了这个解决方案，用于检索我在文章中找到的第二低的列表项：

if minutes < 1:
            soonestDepartureTimeUnix2 = min(item["departure_time"] for item in                tsl105513Route2["itineraries"][0]["schedule_items"] if item != soonestDepartureTimeUnix)
           minutes = int((soonestDepartureTimeUnix2 - (time.time()))/60)

然而这只是再次返回 0。

Answer 1

在生成器中，忽略当前时间之前或等于当前时间的任何时间。

minAllowedDepartureTimeUnix = time.time() + 60
soonestDepartureTimeUnix = min(item["departure_time"] 
                               for item in tsl105513Route2["itineraries"][0]["schedule_items"]
                               if item["departure_time"] >= minAllowedDepartureTimeUnix)