Android Room Database:如何嵌入多个实体

问题描述 投票:7回答:1

我正在为我的新项目使用空间,但是我在如何干净地获取一对一的值方面感到挣扎。我有地址,所有者和站点的实体,所有者和站点都有一个关联的地址,并且每个站点都有一个所有者是否可以干净地访问这些文件,例如site.owner.address.l1

我看过@Relation,尽管它返回的列表不理想

实体

@Entity(tableName="addresses")
data class Address(
    @PrimaryKey
    @ColumnInfo(name="address_id")
    val id: Int,

    @ColumnInfo(name="address_l1")
    val l1: String
)

@Entity(tablename="owners")
data class Owner(
    @PrimaryKey
    @ColumnInfo(name="owner_id")
    val id: Int,

    @ColumnInfo(name="owner_name")
    val name: String
)

@Entity(tableName="sites")
data class Site(
    @PrimaryKey
    @ColumnInfo(name="site_id")
    val id: Int,

    @ColumnInfo(name="site_addressid")
    val addressid: Int

    @ColumnInfo(name="site_ownerid")
    val ownerid: Int
)

Dao's

@Query("SELECT * FROM sites")
fun getSites(): List<Site>

@Query("SELECT * FROM owners")
fun getOwners(): List<Owner>

@Query("SELECT * FROM addresses")
fun getAddresses(): List<Address>

@Query("SELECT * FROM sites JOIN address ON sites.site_addressid = address.address_id JOIN owners ON sites.site_ownerid = owners.owner_id JOIN address ON owners.owner_addressid = address.address_id WHERE sites.site_id = :siteid")
fun getSiteByIdWithDetails(siteid): Site

我只能看到多个POJO的方法来完成这项工作,例如无效,但大致正确

data class OwnerAddress(
    @Embedded
    val owner: Owner,

    @Embedded
    val address: Address
)

data class SiteAddress(
    @Embedded
    val site: Site,

    @Embedded
    val owner: OwnerAddress,

    @Embedded
    val address: Address
}

并通过]使用>

@Query("SELECT * FROM sites JOIN address ON sites.site_addressid = address.address_id JOIN owners ON sites.site_ownerid = owners.owner_id JOIN address ON owners.owner_addressid = address.address_id WHERE sites.site_id = :siteid")
fun getSiteByIdWithDetails(siteid): SiteAddress

我正在为我的新项目使用空间,但是我在如何干净地访问一对一的值方面感到挣扎,我有地址,所有者和站点的实体,所有者和站点都有关联的地址,...

database kotlin persistence android-room
1个回答
0
投票

您是否尝试过在实体之间建立关系? Android Documentation for Relationships

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