在 PHP 中使用 OAuth 进行 Zoom API 请求

Question

我正在尝试向 Zoom API 发出一个简单的 API 请求 - 将注册者插入网络研讨会。 据我所知，我需要获取 OAuth 密钥，然后进行第二次调用以将注册者插入网络研讨会。 我收到一个错误：

“OAuth 请求失败：400 {“reason”：“不支持的授权类型”，“error”：“unsupported_grant_type”}”

这里有一个可以帮助您的解释：

https://developers.zoom.us/docs/api/rest/reference/zoom-api/methods/#operation/webinarRegistrantCreate

https://developers.zoom.us/docs/internal-apps/s2s-oauth/

这是我的代码（我隐藏了 API 密钥、密钥和帐户 ID）：

class Zoom_Api
{

    public function getToken() {
        $url = 'https://zoom.us/oauth/token';
        $data = array(
        'grant_type' => 'account_credentials',
        'account_id' => '*******'
        );
        
        $zoomAPIKey  = '************';
        $zoomSecretKey  = '************';

        $headers = array(
            'Authorization: Basic '. base64_encode($zoomAPIKey.":".$zoomSecretKey)
        );
        
        $curl = curl_init();
        curl_setopt($curl, CURLOPT_URL, $url);
        curl_setopt($curl, CURLOPT_POST, 1);
        curl_setopt($curl, CURLOPT_POSTFIELDS, http_build_query($data));
        curl_setopt($curl, CURLOPT_HTTPHEADER, $headers);
        curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
        $response = curl_exec($curl);


        $httpCode = curl_getinfo($curl, CURLINFO_HTTP_CODE);
        if ($httpCode == 200) {
            // Parse the JSON response to get the access token
            $oauthResponse = json_decode($response, true);
            $accessToken = $oauthResponse['access_token'];
            return $accessToken;
        } else {
            echo 'OAuth Request Failed: ' . $httpCode . PHP_EOL;
            echo $response . PHP_EOL;
            return null;
        }
        
        curl_close($curl);
    }


    public function sentRequest() {
        $name = "testdfdf";
        $email = "[email protected]";
        $webinarID = 867098960000;

        $regData = array(
        'email' => $email,
        'first_name' => $name,

        );

        $jsonStrReg = json_encode($regData);
        $httpStrReg = http_build_query($regData);
        
        $ch = curl_init('https://api.zoom.us/v2/webinars/'.$webinarID.'/registrants');
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

        curl_setopt($ch, CURLOPT_POST, true);
        curl_setopt($ch, CURLOPT_POSTFIELDS, $httpStrReg);

        curl_setopt($ch, CURLOPT_HTTPHEADER, array(
        'Authorization: Bearer ' . $this->getToken()
        ));

        $response = curl_exec($ch);
        $response = json_decode($response);
        curl_close($ch);
        return $response;
    }


}


$zoom_meeting = new Zoom_Api();
$response = $zoom_meeting->getToken();
echo "<pre>";
print_r($response);
echo "<pre>";

有什么问题吗？

Answer 1

我发现了问题：我在 Zoom 上创建了错误的应用程序类型，并且第二个请求中缺少请求数据类型。