如何使用Flask从URL获取命名参数?

问题描述 投票:244回答:6

当用户访问我在烧瓶应用程序上运行的URL时,我希望Web服务能够处理问号后指定的参数:

http://10.1.1.1:5000/login?username=alex&password=pw1

#I just want to be able to manipulate the parameters
@app.route('/login', methods=['GET', 'POST'])
def login():
    username = request.form['username']
    print(username)
    password = request.form['password']
    print(password)
python web-services flask url-parameters
6个回答
437
投票

使用request.args获取查询字符串的已解析内容:

from flask import request

@app.route(...)
def login():
    username = request.args.get('username')
    password = request.args.get('password')

82
投票

URL参数在request.args中可用,MultiDict是一个get,具有default方法,默认值(type)和类型(from flask import request @app.route('/my-route') def my_route(): page = request.args.get('page', default = 1, type = int) filter = request.args.get('filter', default = '*', type = str) )的可选参数 - 可调用,将输入值转换为所需格式。

/my-route?page=34               -> page: 34  filter: '*'
/my-route                       -> page:  1  filter: '*'
/my-route?page=10&filter=test   -> page: 10  filter: 'test'
/my-route?page=10&filter=10     -> page: 10  filter: '10'
/my-route?page=*&filter=*       -> page:  1  filter: '*'

上面代码的示例:

@app.route('/<name>')
def my_view_func(name):
    return name

37
投票

您还可以在视图定义的URL上使用括号<>,此输入将进入您的视图函数参数

from flask import request
#url
http://10.1.1.1:5000/login/alex

from flask import request
@app.route('/login/<username>', methods=['GET'])
def login(username):
    print(username)

21
投票

如果您在URL中传递了一个参数,则可以按如下方式执行此操作

#url
http://10.1.1.1:5000/login?username=alex&password=pw1

from flask import request
@app.route('/login', methods=['GET'])
    def login():
        username = request.args.get('username')
        print(username)
        password= request.args.get('password')
        print(password)

如果您有多个参数:

#url
http://10.1.1.1:5000/login

您尝试执行的操作适用于POST请求,其中参数作为表单参数传递但不显示在URL中。如果您实际上正在开发登录API,建议您使用POST请求而不是GET并将数据公开给用户。

如果是邮寄请求,它将按如下方式工作:

<form action="http://10.1.1.1:5000/login">
  Username : <input type="text" name="username"><br>
  Password : <input type="password" name="password"><br>
  <input type="submit" value="submit">
</form>

HTML片段:

from flask import request
@app.route('/login', methods=['POST'])
    def login():
        username = request.form.get('username')
        print(username)
        password= request.form.get('password')
        print(password)

路线:

http://0.0.0.0:5000/user/name/

3
投票

网址:

@app.route('/user/< string:name >/', methods=['GET', 'POST'])
def user_view(name):
    print(name)

码:

<form method="POST">
<input type="text" name="user_name"></input>
<input type="text" name="password"></input>
</form>

-1
投票

这很简单。让我把这个过程分成两个简单的步骤。

  1. 在html模板上,您将声明用户名和密码的名称标签为 from flask import request @app.route('/my-route', methods=['POST']) #you should always parse username and # password in a POST method not GET def my_route(): username = request.form.get("user_name") print(username) password = request.form.get("password") print(password) #now manipulate the username and password variables as you wish #Tip: define another method instead of methods=['GET','POST'], if you want to # render the same template with a GET request too
  2. 然后,将代码修改为: qazxswpoi
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