如何在 python 中几秒钟后自动关闭 tkinter 的消息框

Question

尝试在不等待用户响应的情况下打开和关闭弹出窗口。

我试过：

    root = Tk()
    root.withdraw()
    try:
        root.after(TIME_TO_WAIT, root.destroy)
        messagebox.showinfo("Output", "somthing")
    except:
        pass

或：

    root = Tk()
    root.withdraw()
    try:
        root.after(TIME_TO_WAIT, root.destroy)
        Message(title="your title", message="somthing", master=root).show()
    except:
        pass

但使用 macOS 时会出现以下问题：

2023-02-28 15:12:08.197 Python[10165:332611] Warning: Expected min height of view: (<NSButton: 0x7fe48210d240>) to be less than or equal to 30 but got a height of 32.000000. This error will be logged once per view in violation.
2023-02-28 15:12:50.709 Python[10165:332611] Warning: Expected min height of view: (<NSButton: 0x7fe480190bf0>) to be less than or equal to 30 but got a height of 32.000000. This error will be logged once per view in violation.
objc[10165]: autorelease pool page 0x7fe47c277000 corrupted
magic     0x00000000 0x00000000 0x00000000 0x00000000
should be 0xa1a1a1a1 0x4f545541 0x454c4552 0x21455341
pthread   0x7ff85525f4c0
should be 0x7ff85525f4c0

Answer 1

我会做一些事情：

import tkinter as tk
import tkinter.messagebox as msgbox

def showMessage(message, timeout=5000):
    root = tk.Tk()
    root.withdraw()
    root.after(timeout, root.destroy)
    msgbox.showinfo('Info', message, master=root)

showMessage('Your Message Here')

Answer 2

这是一个潜在的解决方案，它创建一个

Toplevel

窗口，该窗口在 5 秒后自动关闭。

import tkinter as tk


def close():
    dialog.destroy()
    root.quit()


root = tk.Tk()
root.withdraw()
root.after(5000, close)
# create dialog window
dialog = tk.Toplevel(root)
dialog.geometry('200x100')
dialog.title('Hello')
message = tk.Label(dialog, text='Please Wait...')
message.pack(expand=True, fill='both')


# run app
if __name__ == '__main__':
    root.mainloop()

但是，如果您不想为

tkinter.messagebox

烦恼，您可以跳过创建

Toplevel

窗口，只需使用主窗口作为您的消息对话框！ :)

import tkinter as tk


root = tk.Tk()
root.geometry('200x100')
root.title('Hello')
root.after(5000, root.quit)  # quit the app automatically after 5 sec
message = tk.Label(root, text='Please Wait...')
message.pack(expand=True, fill='both')


# run app
if __name__ == '__main__':
    root.mainloop()