获取内容匹配文件

Question

我想读取文本文件并将文本文件中的内容数据与文件名匹配，然后记录输出。这就是我到目前为止所做的工作：

$Source = "S:\*.*"
$Missing_Files = "C:\Temp\Powershell Scripts\Missing Files Script\Results\"

foreach ($ID in Get-Content 'C:\Temp\Powershell Scripts\Missing Files 
Script\IDS.txt') {
$ID
$Count = 0
Get-Childitem $Source -ErrorAction SilentlyContinue | where {$_.name - 
notmatch $ID} | foreach {
}
if ($Count -eq 0) {
    Write-Host $_.name "No File Found"
    Write-Output $ID "No File Found" | Out-File $Missing_Files\$(Get-Date -f 
yyyy-MM-dd)_Missing_Files_Results.txt -append
    }
}

Answer 1

如果我正确理解了该问题，您需要搜索文本文件中未列出的文件 C:\Temp\Powershell Scripts\Missing Files Script\IDS.txt。

找到但未在该文件中列出的任何文件都被认为是无关的，如果找到了额外的文件，您希望让脚本创建（或追加）结果文件。

在这种情况下，这应该工作：

$SourcePath  = "S:\"
$OutputPath  = "C:\Temp\Powershell Scripts\Missing Files Script\Results"
$OutputFile  = Join-Path -Path $OutputPath -ChildPath ('{0:yyyy-MM-dd}_Missing_Files_Results.txt' -f (Get-Date))
$ListedFiles = Get-Content 'C:\Temp\Powershell Scripts\Missing Files Script\IDS.txt' | Sort-Object -Unique

# get an array of filenames that are NOT listed in 'C:\Temp\Powershell Scripts\Missing Files Script\IDS.txt'
$files = @(Get-Childitem $SourcePath -File -ErrorAction SilentlyContinue | 
           Where-Object { $ListedFiles -notcontains $_.Name })

if ($files.Count) {
    # we found files that are NOT listed
    Write-Host "$($file.Count) Files found that are not listed in '$ListedFiles'"
    Add-Content -Path $OutputFile -Value ($files -join [Environment]::NewLine)
}
else {
    # no files found
    Write-Host "No files found"
    Add-Content -Path $OutputFile -Value "No file found."
}

希望有所帮助