如何获得Oozie的依赖性检查以列出数据集的完整路径名而不是coord:latest(0)?

问题描述 投票:0回答:1

通过Oozie协调器和工作流程,我在协调工作日志中看到以下特定操作:

JOB[0134742-190911204352052-oozie-oozi-C] ACTION[0134742-190911204352052-oozie-oozi-C@1] [0134742-190911204352052-oozie-oozi-C@1]::CoordActionInputCheck:: Missing deps: ${coord:latest(0)}#${coord:latest(0)}#${coord:latest(0)}#${coord:latest(0)}#${coord:latest(0)}#${coord:latest(0)}

似乎缺少完整的路径名。如果在协调器中未使用lastest(0)指定路径名,则路径可用,如下所示:

JOB[0134742-190911204352052-oozie-oozi-C] ACTION[0134742-190911204352052-oozie-oozi-C@1] [0134742-190911204352052-oozie-oozi-C@1]::CoordActionInputCheck:: Missing deps:hdfs://labs-xxx/data/funcxx/inputs/uploads/reports-for-targeting/20190923/14

稍后路径解析为:

JOB[0134742-190911204352052-oozie-oozi-C] ACTION[0134742-190911204352052-oozie-oozi-C@1] [0134742-190911204352052-oozie-oozi-C@1]::ActionInputCheck:: File:hdfs://labs-xxx/data/funcxx/inputs/uploads/reports-for-targeting/20190923/14, Exists? :true

如何查看完整路径名称而不是$ {coord:latest(0)}字符串?

oozie oozie-coordinator oozie-workflow
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您可以通过oozie cli查看此内容-oozie job -info 0134742-190911204352052-oozie-oozi-C@1

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