查询匹配（）导致重复的行，而distinct（）无效

Question

[我正在尝试通过关联的表格发票上的字段过滤一个表格付款。在查询对象上使用功能match（）可以正确过滤，但会导致重复行。似乎解决方案正在使用distinct（），但是调用distinct（Payments.id）会导致无效查询。我正在执行控制器操作中的以下操作。

      $conditions = [
        'Payments.is_deleted =' => false
      ];
      $args = [
        'conditions' => $conditions,
        'contain' => ['Invoices', 'Invoices.Clients'],
      ];
      $payments = $this->Payments->find('all', $args);
      if($issuer) {
        // This causes duplicate rows
        $payments->matching('Invoices', function ($q) use ($issuer) {
          return $q->where(['Invoices.issuer_id' => $issuer['id']]);
        });
        // $payments->distinct('Payments.id'); // Causes a mysql error
      }

我是否认为我需要的是distinct（）是正确的，如果有的话，使它正常工作缺少什么？

取消注释以上行时出现以下mysql错误：

错误：SQLSTATE [42000]：语法错误或访问冲突：1055 SELECT列表的表达式＃8不在GROUP BY子句中，并且包含未聚合的列'InvoicesPayments.id'，该列在功能上不依赖于GROUP BY子句中的列；这与sql_mode = only_full_group_by

不兼容

完整查询：

选择[SELECT PAYMENTS.ID为PAYMENTS__ID，PAYMENTS。创建为PAYMENTS__CREATED，PAYMENTS.MODIFIED为PAYMENTS__MODIFIED，PAYMENTS.DATE_registered为PAYMENTS__DATE_REGISTERED，PAYMENTS.USER_ID为PAYMENTS__USER_ID，PAYMENTS.AMOUNT为PAYMENTS__AMOUNT ，PAYMENTS.IS_DELETED AS PAYMENTS__IS_DELETED，INVOICESPAYMENTS.ID AS INVOICESPAYMENTS__ID，INVOICESPAYMENTS.INVOICE_ID AS INVOICESPAYMENTS__INVOICE_ID，INVOICESPAYMENTS.PAYMENT_ID AS INVOICESPAYMENTS__PAYMENT_ID，INVOICESPAYMENTS.PART_AMOUNT AS INVOICESPAYMENTS__PART_AMOUNT，INVOICES.ID 。创建为INVOICES__ID，INVOICES.IS_PAID为INVOICES__CREATED，INVOICES.IS_DELETED为INVOICES__MODIFIED，INVOICES.CLIENT_ID为INVOICES__IS_PAID，INVOICES.ISSUER_ID为INVOICES__IS_DELETED，INVOICES.NUMBER AS INVOICES__CLIENT_ID，INVOICES.SUBTOTAL AS INVOICES__ISSUER_ID，INVOICES.TOTAL AS INVOICES__NUMBER，INVOICES.DATE_located AS INVOICES__SUBTOTAL，INVOICES.CURRENCY AS INVOICES__TOTAL，INVOICES.RECEIVER_NAME AS INVOICES__DATE_REGISTERED，INVOICES.RECEIVER_RFC AS [ C0]，INVOICES.EMAIL_SENDER AS INVOICES__CURRENCY，INVOICES.PDF_PATH AS INVOICES__RECEIVER_NAME，来自PAYMENTS.ID =（INVOICESPAYMENTS.PAYMENT_ID）的PAYMENTS PAYMENTS内联INVOICES_PAYMENTS INVOICES。 ID =（INVOICESPAYMENTS.INVOICE_ID ））（WHERE（PAYMENTS.IS_DELETED =：C1 AND PAYMENTS.DATE_register> =：C2 AND PAYMENTS.DATE_register <=：C3）GROUP BY PAYMENT_ID OR BY BY PAYMENTS.DATE_register ASC

Answer 1

mysql中sql_mode值的问题，因此您需要将sql_mode值设置为空白，然后可以尝试为您工作正常。

INVOICES__RECEIVER_RFC

[请让我知道其他内容。