在 MYSQL 中更新插入多个表

Question

我正在尝试创建代码，以便在更新 1 个或多个源表时更新表（从 2 个联接创建）。

这是原始代码：

REPLACE INTO operations (
    customerId,
    customerCreated
    _Id
    paymentsCreated
    status,
    amounts,
    commerceName)
SELECT
    cu.customerId,
    cu.customerCreated
    p._Id
    p.paymentsCreated
    p.status,
    p.amounts,
     c.commerceName)
FROM
    payments p
LEFT JOIN
  commerces c ON c._id = p.commerceId
LEFT JOIN 
  customers cu ON cu.customerId = p.customerId

如您所见，有 3 个表，每个表都可以通过修改很久以前创建的记录来随时更改。

嗯，我正在尝试使用这段代码，但我不知道它是否是最好的选择，并且它是最快的，因为表有数百万条记录。

REPLACE INTO operations (
    customerId,
    customerCreated,
    _Id,
    paymentsCreated,
    status,
    amounts,
    commerceName
)
SELECT
    cu.customerId,
    cu.customerCreated,
    p._Id,
    p.paymentsCreated,
    p.status,
    p.amounts,
    c.commerceName
FROM
    payments p
LEFT JOIN
    commerces c ON c._id = p.commerceId
LEFT JOIN 
    customers cu ON cu.customerId = p.customerId
WHERE
    cu.updated >= DATE_SUB(CURDATE(), INTERVAL 1 DAY) OR
    p.updated >= DATE_SUB(CURDATE(), INTERVAL 1 DAY) OR
    c.updated >= DATE_SUB(CURDATE(), INTERVAL 1 DAY);

Answer 1

假设您在

updated

列上有索引，将您的选择拆分为三个单独的选择，然后将它们与 UNION 组合可能会效果更好。

SELECT cu.customerId, cu.customerCreated, p._Id, p.paymentsCreated, p.status, p.amounts, c.commerceName
FROM payments p
LEFT JOIN commerces c ON c._id = p.commerceId
LEFT JOIN customers cu ON cu.customerId = p.customerId
WHERE p.updated >= DATE_SUB(CURDATE(), INTERVAL 1 DAY)

UNION

SELECT cu.customerId, cu.customerCreated, p._Id, p.paymentsCreated, p.status, p.amounts, c.commerceName
FROM payments p
INNER JOIN commerces c ON c._id = p.commerceId
LEFT JOIN customers cu ON cu.customerId = p.customerId
WHERE c.updated >= DATE_SUB(CURDATE(), INTERVAL 1 DAY)

UNION

SELECT cu.customerId, cu.customerCreated, p._Id, p.paymentsCreated, p.status, p.amounts, c.commerceName
FROM payments p
LEFT JOIN commerces c ON c._id = p.commerceId
INNER JOIN customers cu ON cu.customerId = p.customerId
WHERE cu.updated >= DATE_SUB(CURDATE(), INTERVAL 1 DAY);