在laravel中一起加入两个查询

Question

我有这个功能：

    public function landings($slug){
        $landing = Landing::where('slug', $slug)->firstOrFail();

    //use to get categories id stored in DB
        $cat = DB::table('landing_categories')->where('landing_id', $landing->id)->get();
        foreach ($cat as $key) {
          $id[] = $key->category_id;
        }

// use to get specifications id and compare it with products that have same specifications id's
        $subs = DB::table('landing_specifications')->where('landing_id', $landing->id)
        ->join('product_subspecification', function ($keys) {
            $keys->on('product_subspecification.subspecification_id', '=', 'landing_specifications.subspecification_id');
        })
        ->join('products', 'products.id', '=', 'product_subspecification.product_id')
        ->get();
    // dd($subs);

// using this to get result of 2 queries above at once
        $prod = DB::table('products')
        ->whereIn('products.category_id', $id)
        ->groupby($subs)
        ->get();
        return view('front.landing', compact('landing', 'prod'));
      }

查询：$cat和$subs按预期工作并返回我正在寻找的结果。

我的问题是如何在$prod查询中绑定这两个？

到目前为止，我可以使用cat的whereIn但是你看到$subs和$prod都试图获得DB::table('products')，这就是我猜的问题。

我得到的这个错误：

SQLSTATE [HY093]：无效的参数编号：混合的命名和位置参数（SQL：select * from products，其中products.category_id in（3,4）group by`[{“id”：1，“landing_id”：8，“s // 未完待续...

PS：如果我使用->union($subs)而不是->groupby($subs)，我会得到：

方法getBindings不存在。

UPDATE

dd($id);

array:2 [▼
  0 => 3
  1 => 4
]

dd($subs);

Collection {#721 ▼
  #items: array:5 [▼
    0 => {#710 ▼
      +"id": 1
      +"landing_id": 8
      +"subspecification_id": 1
      +"product_id": 1
      +"title": "product one"
      +"slug": "product-one"
      +"imageOne": "product-1517990897.jpg"
      +"imageTwo": "product-1517990897.png"
      +"short_description": "<p>this is first testing product</p>"
      +"description": "<p>this is first testing product this is first testing product this is first testing product this is first testing product this is first testing product this is ▶"
      +"price": "10000000"
      +"meta_description": null
      +"meta_tags": null
      +"arrivalDays": "2"
      +"height": "100"
      +"weight": "1"
      +"lenght": "100"
      +"width": "100"
      +"sku": "1985629"
      +"stock": "16"
      +"status_id": 1
      +"brand_id": 2
      +"category_id": 1
      +"subcategory_id": 2
      +"created_at": "2018-02-07 15:05:00"
      +"updated_at": "2018-02-28 14:16:46"
    }
    1 => {#716 ▶}
    2 => {#714 ▶}
    3 => {#720 ▶}
    4 => {#718 ▶}
  ]
}

PS：当我将$cat和$subs放在一起时，应该将结果减少到1，这是我保存的y数据的正确答案。

Answer 1

SOLVED

我混合了我的$subs和$prod，如下所示，它的工作完美：

$prod = DB::table('landing_specifications')->where('landing_id', $landing->id)
    ->join('product_subspecification', function ($keys) {
        $keys->on('product_subspecification.subspecification_id', '=', 'landing_specifications.subspecification_id');
    })
    ->join('products', 'products.id', '=', 'product_subspecification.product_id')
    ->whereIn('products.category_id', $id)
    ->groupby('products.id')
    ->get();