该功能并没有在while循环计数器响应

Question

所以，我提出要达到12个等级A while循环。计数器从0开始在Main()方法我称之为功能gradeFunction()但执行后，它不会不进行任何更改计数器。

Program p = new Program();
string name = Console.ReadLine();
int gradesPassed = 12;
int currentGrade = 0;
double totalSumOfGrades = 0;
while(currentGrade <= gradesPassed)
{
    double finalGrade = double.Parse(Console.ReadLine());
    p.gradeFunction(finalGrade, totalSumOfGrades,     currentGrade);
}

被调用的函数：

public void gradeFunction(double finalGrade, double totalSumOfGrades, int currentGrade)
{
    if(finalGrade >= 4.00)
    {
       totalSumOfGrades += finalGrade;
       currentGrade++;
    }

}

Answer 1

就像@Jeremy说，请尝试以下操作：

Program p = new Program();
string name = Console.ReadLine();
int gradesPassed = 12;
int currentGrade = 0;
double totalSumOfGrades = 0;
while (currentGrade <= gradesPassed)
{
    double finalGrade = double.Parse(Console.ReadLine());
    gradeFunction(finalGrade, ref totalSumOfGrades, ref currentGrade);
}

public static void gradeFunction(double finalGrade, ref double totalSumOfGrades, ref int currentGrade)
        {
            if (finalGrade >= 4.00)
            {
                totalSumOfGrades += finalGrade;
                currentGrade++;
            }

        }

我已经加入裁判关键字currentGrade和totalSumOfGrades在电话和声明都让变量被正确地更新，我相信是最无冲击的方式来获取代码工作。

Answer 2

编码，

    Console.ReadLine();
    double totalSumOfGrades = 0;

    for(var currentGrade = 0; currentGrade <= 12; currentGrade++)
    {
        var finalGrade = double.Parse(Console.ReadLine());
        if (finalGrade >= 4.00)
        {
            totalSumOfGrades += finalGrade;
        }
    }

会更简单，更直接。