未使用笑话调用异步等待功能

Question

我是开玩笑的新手，我正试图调用await函数，它会返回承诺。但是我收到错误消息，例如预期的呼叫1和已接的呼叫为0

代码：

public async callDataSourceCommand(dialogData: any, RecipeId: string) {

   const gridItems = await this.dataSourceService.myPromiseMethod(id, collection);

}

MockData

 public get dataSourceServiceMock(): any = {
     return {
        myPromiseMethod: function () {
            return Promise.resolve({
                id: '123',
                collection: []
              });
        }
    }
}

测试套件

it('1. Should execute ', async() => {
    const myDialogApp: DialogApp = TestBed.get(DialogApp);
    myDialogApp.selectedOrder = selectedOrder;
    myDialogApp.RecipeId = Recipe.__id;
    myDialogApp.callDataSourceCommand(dialogData, RecipeId);
    jest.spyOn(dataSourceServiceMock, 'myPromiseMethod');
    expect(dataSourceServiceMock.myPromiseMethod).toHaveBeenCalled();
});

Answer 1

正如Jaromanda正确编写的，您需要await异步方法。同样，您需要在执行操作之前而不是执行操作之后监视该方法。这是一个您可以直接运行的示例。

class MyDialogApp {
  constructor(private dataSourceService: any) {}

  public async callDataSourceCommand() {
    await this.dataSourceService.myPromiseMethod();
  }
}

const dataSourceServiceMock = {
  myPromiseMethod: function() {
    return Promise.resolve({
      id: '123',
      collection: []
    });
  }
};

const myDialogApp = new MyDialogApp(dataSourceServiceMock);

it('1. Should execute ', async () => {
  // arrange
  jest.spyOn(dataSourceServiceMock, 'myPromiseMethod');

  // act
  await myDialogApp.callDataSourceCommand();

  // assert
  expect(dataSourceServiceMock.myPromiseMethod).toHaveBeenCalled();
});