java.sql.Timestamp中没有默认构造函数

Question

我用Java编写我的web服务，并有一两件事，我卡住了。我想送的java.sql.Timestamp作为一个JSON响应，但得到了IllegalAnnotationException。我使用的球衣1.19以下是例外。

javax.ws.rs.WebApplicationException:
com.sun.xml.bind.v2.runtime.IllegalAnnotationsException: 1 counts of IllegalAnnotationExceptions
java.sql.Timestamp does not have a no-arg default constructor.
this problem is related to the following location:
    at java.sql.Timestamp
    at public java.sql.Timestamp response.TransactionStatusResponse.command_receiving_datetime
    at response.TransactionStatusResponse
    at public java.util.List response.OnDemandRequestResponse.getData()
    at response.OnDemandRequestResponse

下面显示的是我的JsonResponseModel类。

@XmlRootElement
public class TransactionStatusResponse {

     public TransactionStatusResponse() {
     }  

     public String transaction_id;
     public String msn;
     public String global_device_id;
     public String type;
     public String type_parameters;
     public Timestamp command_receiving_datetime;

}

我也看到了java.sql.Timestamp中的类，它没有默认的构造函数。那么，有没有什么办法可以不发送默认参数的构造函数对象JSON响应。

Answer 1

我认为你需要为此注册适配器

public class TimestampAdapter extends XmlAdapter<Date, Timestamp> {
      public Date marshal(Timestamp v) {
          return new Date(v.getTime());
      }
      public Timestamp unmarshal(Date v) {
          return new Timestamp(v.getTime());
      }
  }

那么你的注释像时间戳

@XmlJavaTypeAdapter( TimestampAdapter.class)
        public Timestamp done_date;

你应该使用java.util.Date代替java.sql.Date