我有一个嵌套列表,如下所示:
nested.list <- list(c(46270L, 103154L, 159944L, 193405L, 199925L), c(24049L,
30454L, 55710L, 106407L, 122059L, 174131L), c(14520L, 46270L,
153636L, 188626L, 199925L), c(8150L, 24049L, 27321L, 30461L,
33513L, 55710L, 58933L, 71342L, 103154L, 122059L, 159920L, 169516L,
174131L), c(19195L, 71333L, 122059L, 137645L, 153636L, 183740L,
195065L, 199925L), c(14520L, 60368L, 80939L, 82381L, 95070L,
103172L, 106379L, 147215L, 166353L, 199925L), c(30461L, 68324L,
75981L, 77674L, 106407L, 120284L), c(24029L, 72751L, 103154L,
120284L, 142359L))
> nested.list
[[1]]
[1] 46270 103154 159944 193405 199925
[[2]]
[1] 24049 30454 55710 106407 122059 174131
[[3]]
[1] 14520 46270 153636 188626 199925
[[4]]
[1] 8150 24049 27321 30461 33513 55710 58933 71342 103154 122059 159920 169516 174131
[[5]]
[1] 19195 71333 122059 137645 153636 183740 195065 199925
[[6]]
[1] 14520 60368 80939 82381 95070 103172 106379 147215 166353 199925
[[7]]
[1] 30461 68324 75981 77674 106407 120284
[[8]]
[1] 24029 72751 103154 120284 142359
在每个列表中,我只想保留这些数字。
target.values <- c(24030L, 33514L, 60369L, 106408L, 147216L, 153637L, 159921L,
193406L)
我尝试过
purrr::keep(.x = nested.list, .p = function(x){all(x %in% target.values)})
,但显然我错过了一些关于它是如何工作的。
map(nested.list, keep, \(x) x %in% target.values)