如何在android中确认密码？

Question

我有两个EditText，一个用于输入密码，另一个用于确认此密码。这些编辑文本的最大长度为5。

confirmPwdEdiText.addTextChangedListener(new TextWatcher() {
 public void afterTextChanged(Editable s) {}
 public void beforeTextChanged(CharSequence s, int start, int count,
     int after) { }

 public void onTextChanged(CharSequence charSequence, int start, int before, int count)        
 {

   String pwd = passwordEdiText.getText().toString();
   String confirmaion = charSequence.toString();
   if ((pwd == null || pwd.trim().length() <= 0) &&  confirmaion.trim().length() > 0) {
           Toast.makeText(context,"Enter password",Toast.LENGTH_SHORT).show();
   } 
   else if (pwd != null && pwd.trim().length() > 0 ) {
      if(confirmaion.trim().length() == pwd.length()) {
         if (pwd.equals(confirmaion)) {
            password = pwd;
            Toast.makeText(context,"Passwords match",Toast.LENGTH_SHORT).show();
         } 
         else {
            Toast.makeText(context,"Passwords do not match",Toast.LENGTH_SHORT).show();
         }
      }
   }
 }
});

当我使用此密码确认密码时，删除密码时会再次显示'密码不匹配'吐司。如何有效地确认密码不使用按钮点击或任何其他方法>？]

预先感谢

我有两个EditText，一个用于输入密码，另一个用于确认此密码。这些编辑文本的最大长度为5。ConfirmPwdEdiText.addTextChangedListener（new TextWatcher（）{public void ...

Answer 1

您可以使用TextWatcher

Answer 2

Answer 3

    @Override
public void afterTextChanged(Editable s) {

    System.out.println(s.toString());
    String oldPass = oldPassword.getText().toString();
    String newPass = newPassword.getText().toString();
    String confirmPass = confirmPassword.getText().toString();
    if (!oldPass.equals("") && !newPass.equals("") && oldPass.equals(newPass)) {
        Toast.makeText(getContext(), "Choose Different Password than Old Password", Toast.LENGTH_SHORT).show();
    }
    else if (!newPass.equals("") && !confirmPass.equals("") && !newPass.equals(confirmPass) && newPass.length()==confirmPass.length())
    {
        Toast.makeText(getContext(), "Choose same as New Password", Toast.LENGTH_SHORT).show();
    }
}

Answer 4