对于某个特定用户,表中的数字显示错误。数据直接来自数据库。数据库或后端没有问题。我附上问题的图片。连同代码片段。
var salesJson = JSON.parse("{{ DSsales | escapejs }}");
var sales = new google.visualization.DataTable(salesJson, 0.6);
const drawTableB = function (
aggregateArr,
groupByArr = [0],
datatable = sales
) {
const aggregateObjArr = aggregateArr.map((x) => {
return {
column: x,
aggregation: google.visualization.data.avg,
type: "number",
};
});
console.log(groupByArr)
const table_B_view_1 = google.visualization.data.group(
datatable,
groupByArr,
aggregateObjArr
);
const table_B_options = {
allowHtml: true,
title: "Opening by Brand Current Month vs Previous Month",
alternatingRowStyle: false,
cssClassNames: {
headerCell: "table-header-cells",
tableCell: "table-row-cells",
},
width: "100%",
height: "100%",
sort: "disable",
};
document.getElementById("table_B_card").classList.remove("d-none");
var table_B = new google.visualization.Table(
document.getElementById("table_B")
);
table_B.draw(table_B_view_1, table_B_options);
}
确保替换 {{ DSsales | escapejs }} 与 salesJson 的实际数据源。此外,请检查其余代码是否存在可能影响 Google Charts API 行为的任何潜在问题。如果您遇到特定错误或意外行为,请提供更多详细信息,以便我可以为您提供进一步帮助。
const drawTableB = function(aggregateArr, groupByArr = [0]) {
try {
// Parse JSON data
const salesJson = JSON.parse("{{ DSsales | escapejs }}");
// Initialize DataTable
const sales = new google.visualization.DataTable(salesJson, 0.6);
// Map aggregate columns
const aggregateObjArr = aggregateArr.map(column => ({
column,
aggregation: google.visualization.data.avg,
type: "number"
}));
// Group data
const table_B_view_1 = google.visualization.data.group(
sales,
groupByArr,
aggregateObjArr
);
// Table options
const table_B_options = {
allowHtml: true,
title: "Opening by Brand Current Month vs Previous Month",
alternatingRowStyle: false,
cssClassNames: {
headerCell: "table-header-cells",
tableCell: "table-row-cells",
},
width: "100%",
height: "100%",
sort: "disable",
};
// Update DOM element
document.getElementById("table_B_card").classList.remove("d-none");
// Draw table
const table_B = new google.visualization.Table(
document.getElementById("table_B")
);
table_B.draw(table_B_view_1, table_B_options);
} catch (error) {
console.error("Error drawing table:", error);
}
};