日安
我正试图在R中把一个数据集的最后一列移动到数据框架的第三列，我想知道什么是最有效的方法。
我的DataFrame结构如下。
str(HR)
'data.frame': 2940 obs. of 36 variables:
$ EmployeeNumber : int 1 2 3 4 5 6 7 8 9 10 ...
$ Attrition : Factor w/ 2 levels "No","Yes": 2 1 2 1 1 1 1 1 1 1 ...
$ Age : int 41 49 37 33 27 32 59 30 38 36 ...
$ BusinessTravel : Factor w/ 3 levels "Non-Travel","Travel_Frequently",..: 3 2 3 2 3 2 3 3 2 3
$ DailyRate : int 1102 279 1373 1392 591 1005 1324 1358 216 1299 ...
$ Department : Factor w/ 3 levels "Human Resources",..: 3 2 2 2 2 2 2 2 2 2 ...
$ DistanceFromHome : int 1 8 2 3 2 2 3 24 23 27 ...
$ Education : int 2 1 2 4 1 2 3 1 3 3 ...
$ EducationField : Factor w/ 6 levels "Human Resources",..: 2 2 5 2 4 2 4 2 2 4 ...
$ EmployeeCount : int 1 1 1 1 1 1 1 1 1 1 ...
$ EnvironmentSatisfaction : int 2 3 4 4 1 4 3 4 4 3 ...
$ Gender : Factor w/ 2 levels "Female","Male": 1 2 2 1 2 2 1 2 2 2 ...
$ HourlyRate : int 94 61 92 56 40 79 81 67 44 94 ...
$ JobInvolvement : int 3 2 2 3 3 3 4 3 2 3 ...
$ JobLevel : int 2 2 1 1 1 1 1 1 3 2 ...
$ JobRole : Factor w/ 9 levels "Healthcare Representative",..: 8 7 3 7 3 3 3 3 5 1 ...
$ JobSatisfaction : int 4 2 3 3 2 4 1 3 3 3 ...
$ MaritalStatus : Factor w/ 3 levels "Divorced","Married",..: 3 2 3 2 2 3 2 1 3 2 ...
$ MonthlyIncome : int 5993 5130 2090 2909 3468 3068 2670 2693 9526 5237 ...
$ MonthlyRate : int 19479 24907 2396 23159 16632 11864 9964 13335 8787 16577 ...
$ NumCompaniesWorked : int 8 1 6 1 9 0 4 1 0 6 ...
$ Over18 : Factor w/ 1 level "Y": 1 1 1 1 1 1 1 1 1 1 ...
$ OverTime : Factor w/ 2 levels "No","Yes": 2 1 2 2 1 1 2 1 1 1 ...
$ PercentSalaryHike : int 11 23 15 11 12 13 20 22 21 13 ...
$ PerformanceRating : int 3 4 3 3 3 3 4 4 4 3 ...
$ RelationshipSatisfaction: int 1 4 2 3 4 3 1 2 2 2 ...
$ StandardHours : int 80 80 80 80 80 80 80 80 80 80 ...
$ StockOptionLevel : int 0 1 0 0 1 0 3 1 0 2 ...
$ TotalWorkingYears : int 8 10 7 8 6 8 12 1 10 17 ...
$ TrainingTimesLastYear : int 0 3 3 3 3 2 3 2 2 3 ...
$ WorkLifeBalance : int 1 3 3 3 3 2 2 3 3 2 ...
$ YearsAtCompany : int 6 10 0 8 2 7 1 1 9 7 ...
$ YearsInCurrentRole : int 4 7 0 7 2 7 0 0 7 7 ...
$ YearsSinceLastPromotion : int 0 1 0 3 2 3 0 0 1 7 ...
$ YearsWithCurrManager : int 5 7 0 0 2 6 0 0 8 7 ...
$ AttritionB : num 1 0 1 0 0 0 0 0 0 0 ...
我想让AttritionB出现在Attrition之后。
HRCorForm = HR[,c(1,2,36:35)]我试过这段代码，但是它否定了其余的列。
善意的问候Rehaan
这将得到你所有的列。
HRCorForm = HR[,c(1,2,36,3:35)]