使用Java中的dom解析器将xml文件转换为json对象

Question

[尝试将任何类型的XML文件转换为JSON对象结构。不同的xml文件具有不同深度的元素和子元素。当具有相同名称的元素在相同高度时创建数组我需要一个为任何结构化XML文件创建精确JSON对象的递归函数

Answer 1

/*
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 * and open the template in the editor.
 */

/**
 *
 * @author nikunj.m
 */
import java.io.File;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import net.sf.json.JSONArray;
import net.sf.json.JSONObject;
import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;

public class xmlTojsonDom1 {

public static void main(String[] args) {
    try {
        File file = new File("D:/Noname1.xml");
        DocumentBuilder dBuilder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
        Document doc = dBuilder.parse(file);
        System.out.println("Root element :" + doc.getDocumentElement().getNodeName());
        if (doc.hasChildNodes()) {
            JSONArray ddd = printNote_1(doc.getChildNodes());
            System.out.println("ddd ::::: " + ddd);
        }
    } catch (Exception e) {
        System.out.println(e.getMessage());
    }
}

private static JSONArray printNote_1(NodeList nodeList) {
    JSONArray dataArr = new JSONArray();
    JSONObject dataObject = new JSONObject();
    for (int count = 0; count < nodeList.getLength(); count++) {
        Node tempNode = nodeList.item(count);
        if (tempNode.getNodeType() == Node.ELEMENT_NODE) {
            if (tempNode.hasChildNodes() && tempNode.getChildNodes().getLength() > 1) {
                JSONArray temArr = printNote_1(tempNode.getChildNodes());
                if (dataObject.containsKey(tempNode.getNodeName())) {
                    dataObject.getJSONArray(tempNode.getNodeName()).add(temArr.getJSONObject(0));
                } else {
                    dataObject.put(tempNode.getNodeName(), temArr);
                }
            } else {
                dataObject.put(tempNode.getNodeName(), tempNode.getTextContent());
            }
        }
    }
    dataArr.add(dataObject);
    return dataArr;
}

}

Answer 2

Please refere this

XmlMapper xmlMapper =新的XmlMapper（）;

String xml = FileUtils.readFileToString（new File（“ test_4.xsd.xml”），Charset.defaultCharset（））;

JsonNode节点= xmlMapper.readTree（xml.getBytes（））;

ObjectMapper jsonMapper =新的ObjectMapper（）;

String json = jsonMapper.writeValueAsString（node）;

System.out.println（json）;