在宏汇编器中连接

问题描述 投票:0回答:1

我想在我的代码中使用类似的东西:

.data?
my_macro_var db MAX_PATH DUP (?)

.code

mov esi, offset my_macro_var 
my_macro esi, "hello and bye"

为此,我创建了这个宏,但我遇到了一些无法解决的错误..

my_macro macro reg, characters  
 LOCAL v1,v2,v3
 LOCAL c1,c2,c3,c4,cTotal

 v1 TEXTEQU  %(@SizeStr(<characters>)) -2 ;; -2 is for the double quote
 v2 textequ %(v1/4) 
 v3 = 0 

 ;% echo @SubStr(<characters>, 2, 4)   

 repeat v2     
     c1 Substr <characters>,v3,1

     cTotal equ c1
     mov dword ptr [reg+v3], cTotal
     v3=v3+4
 endm

endm

我想要这个结果..

mov dword ptr [esi+00d], 'lleh'
mov dword ptr [esi+04d], 'na o'
mov dword ptr [esi+08d], 'yb d'
mov dword ptr [esi+12d], 'e' 

这是我得到的错误:

Code.asm(14) : error A2090: positive value expected
MacroLoop(1): iteration 1: Macro Called From 
my_macro(16): Macro Called From
Code.asm(14): Main Line Code
Code.asm(14) : error A2006: undefined symbol : a
MacroLoop(4): iteration 1: Macro Called From 
my_macro(16): Macro Called From
Code.asm(14): Main Line Code
Code.asm(14) : error A2006: undefined symbol : l
MacroLoop(4): iteration 2: Macro Called From 
my_macro(16): Macro Called From
Code.asm(14): Main Line Code
Code.asm(14) : error A2006: undefined symbol : a
MacroLoop(4): iteration 3: Macro Called From 
my_macro(16): Macro Called From
Code.asm(14): Main Line Code

我认为如果我可以使用 substr 并连接 4 个变量,我的问题就会得到解决...

assembly macros masm masm32
1个回答
2
投票

第一个错误是由于 SUBSTR 使用基于零的索引而您尝试使用基于零的索引这一事实引起的。其余错误是 cTotal 没有引号字符导致的。

因此要修复错误,请尝试以下操作:

my_macro macro reg, characters  
 LOCAL v1,v2,v3
 LOCAL c1,c2,c3,c4,cTotal

 v1 TEXTEQU  %(@SizeStr(<characters>)) -2 ;; -2 is for the double quote
 v2 textequ %(v1/4) 
 v3 = 0

 ;% echo @SubStr(<characters>, 2, 4)   

 repeat v2     
     c1 Substr <characters>, v3 + 1, 4

     cTotal CATSTR <'>, c1, <'>
     mov dword ptr [reg+v3], cTotal
     v3=v3+4
 endm

endm
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