如何在cvxpy中反转变量矩阵?

问题描述 投票:1回答:1

如何在cvxpy中反转变量矩阵?

我有一个问题变量矩阵定义如下:

import cvxpy as cp
A = cp.Variable(2,2)

我想用一个涉及该矩阵的逆的目标函数来求解一个程序。我已经尝试了几乎所有我能想到的方法(包括手动定义逆矩阵),但似乎没有任何工作。

我的问题的完整代码是:

A = cp.Variable((2,2)) # matrix A is 2X2
c = cp.Variable(2) # center of 2d ellipsoid

constraints = [A >> 0]
constraints += [cp.pnorm(cp.matmul(A, v[i] - cp.matmul(A,c)), p=2) <= np.array([1,1]) for i in range(10)]

# this is where I'm stuck. Using np.linalg.inv doesn't work.
# I also can't seem to calculate this inverse manually 
obj_fn = cp.log_det(np.linalg.inv(A))

prob = cp.Problem(cp.Minimize(obj_fn), constraints)
prob.solve(solver='CVXOPT')
python cvxpy cvxopt
1个回答
1
投票

我不知道如何在cvxpy中反转矩阵,但对于您拥有的特定代码,您可以使用以下事实:

记录它A ^ { - 1} = - 记录它A.

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