为什么我要在没有IDE中显示任何错误的情况下获得退出代码-1？

Question

我目前正在使用Python进行编码，我不知道为什么，我编写的程序无法按预期工作。基本上，我正在尝试制作一个密码生成器，但是在输入之后，它就会中断。

import string
import random

nspecialchr = int(input("Number special characters: "))
nnum = int(input("Number of Numbers in password: "))
NChr = int(input("Number of letters: "))

LSpecialChr = ['!', '§', '$', '%', '&', '/', '#']
FLSecialChr = []
while nspecialchr > 0:
    FLSecialChr.append(LSpecialChr[random.randint(0, 6)])
    nspecialchr -= 1
FSpecialChr = ''.join(FLSecialChr)

LNnum = []
while nnum > 0:
    LNnum.append(random.randint(0, 9))
FNum = ''.join(LNnum)

LChr = []
while NChr > 0:
    LChr.append(random.choice(string.ascii_letters))
    NChr -= 1
FChr = ''.join(LChr)

print(FSpecialChr + FNum + FChr)
pasue = input()

Answer 1

我认为您在第二个循环的末尾错过了nnum -= 1（因此您有一个无限循环）。最好写

for i in range(nnum):
    LNnum.append(random.randint(0, 9))

Answer 2

您的代码有几个错误，在您的第二个while循环中，您错过了nnum -= 1，我已修复它们，请尝试以下操作：

import string
import random

nspecialchr = int(input("Number special characters: "))
nnum = int(input("Number of Numbers in password: "))
NChr = int(input("Number of letters: "))

LSpecialChr = ['!', '§', '$', '%', '&', '/', '#']
FLSecialChr = []
while nspecialchr > 0:
    FLSecialChr.append(LSpecialChr[random.randint(0, 6)])
    nspecialchr -= 1
FSpecialChr = ''.join(FLSecialChr)

LNnum = ''
while nnum > 0:
    LNnum+=str(random.randint(0, 9))
    nnum -= 1
FNum = ''.join(LNnum)

LChr = []
while NChr > 0:
    LChr.append(random.choice(string.ascii_letters))
    NChr -= 1
FChr = ''.join(LChr)
print(FSpecialChr + FNum + FChr)
pasue = input() 

输出：

Number special characters: 5                                                                                          
Number of Numbers in password: 4                                                                                      
Number of letters: 3                                                                                                  
password generated is $#$%%1469Fsy