Coleman-Liau索引计算器-IndentationError:意外缩进-为什么?

问题描述 投票:1回答:1

我试图弄清楚如何使我的代码运行,但是没有运气。我的代码应该计算文本的Coleman-Liau索引分数。运行代码时,我收到“ IndentationError:意外缩进”。但是对我来说,它不喜欢看起来代码有什么问题...我还应该提到我对编码还很陌生,所以我可能会遗漏一些明显的东西。关于如何解决IndentationError的任何反馈将不胜感激!(请参见下面的代码)

导入CS50导入数学

def main():text = get_string(“在此处插入文本:”)

lettercounter = 0

wordcounter = 0

sentencecounter = 0

#checks if the letters are in the alphabet.
for i in text:

    if (i.isalpha()):

        lettercounter += 1

    # cheks for words
    elif   i == " ":

        wordcounter += 1

    elif i in [".", "!", "?"]:

        sentencecounter += 1


L = lettercounter * 100 / wordcounter

S = sentencecounter * 100 / sentencecounter


# Coleman-Liau Index Score function
ColemanLiauIndexScore = round(0.0588 * L - 0.296 * S - 15.8)


# printing results
    if ColemanLiauIndexScore > 16):

        print ("grade 16+")

    elif ColemanLiauIndexScore < 1):

        print ("before grade 1")

    else:

        print(f"Grade {difficulty}")

执行主程序

main()

python indentation
1个回答
0
投票
L = lettercounter * 100 / wordcounter

S = sentencecounter * 100 / sentencecounter


# Coleman-Liau Index Score function
ColemanLiauIndexScore = round(0.0588 * L - 0.296 * S - 15.8)


# printing results
    if ColemanLiauIndexScore > 16):

        print ("grade 16+")

    elif ColemanLiauIndexScore < 1):

        print ("before grade 1")

    else:

        print(f"Grade {difficulty}")

注意此行> # printing results之后,您的行具有意外缩进此块不在循环或函数中,因此没有理由在其中缩进。

# printing results
    if ColemanLiauIndexScore > 16):

向左冲洗ifelif,错误应该消失了。

# printing results
if ColemanLiauIndexScore > 16):
    print ("grade 16+")

elif ColemanLiauIndexScore < 1):
    print ("before grade 1")

else:
    print(f"Grade {difficulty}")
© www.soinside.com 2019 - 2024. All rights reserved.