嵌套字典列表到使用理解列表基于键的另一个字典列表

问题描述 投票:0回答:1

我正在尝试使用理解列表将一个词典列表嵌套到另一个词典列表中,我有两个词典列表,一个是类别,另一个是油脂。如果油类category_id等于类别ID,则将清单油的结果添加到每个类别。

def nest(parent, child):
    items = []
    for element in child:
        if element.get('category_id') == parent.get('id'):
            items.append(element)
        parent.update({'items': items})
    return parent

def merge(parent, child):
    results = []
    for element in parent:
        results.append(nest(element, child))
    return results


categories = [
    {'id': 1000, 'name': 'Single'},
    {'id': 2000, 'name': 'Blend'}]

oils = [
    {'id': 100, 'name': 'Orange', 'category_id': 1000},
    {'id': 101, 'name': 'Lavender', 'category_id': 1000},
    {'id': 102, 'name': 'Peppermint', 'category_id': 1000},
    {'id': 104, 'name': 'Inspired', 'category_id': 2000},
    {'id': 105, 'name': 'Focus', 'category_id': 2000},
    {'id': 107, 'name': 'Tea Tree', 'category_id': 1000}]

results = merge(categories, oils)

print(results)
# output:
# [
#     {'id': 1000, 'name': 'Single', 'items': [
#         {'id': 100, 'name': 'Orange', 'category_id': 1000}, 
#         {'id': 101, 'name': 'Lavender', 'category_id': 1000}, 
#         {'id': 102, 'name': 'Peppermint', 'category_id': 1000}, 
#         {'id': 107, 'name': 'Tea Tree', 'category_id': 1000}
#     ]}, 
#     {'id': 2000, 'name': 'Blend', 'items': [
#         {'id': 104, 'name': 'Inspired', 'category_id': 2000}, 
#         {'id': 105, 'name': 'Focus', 'category_id': 2000}
#     ]}
# ]

我正在尝试将以上内容转换为理解列表,但没有成功

merged = [
    element.update({'items': nest}) for nest in oils
    for element in categories if element.get('id') == nest.get('category_id')
]

print(merged)
# output: [None, None, None, None, None, None]
python-3.x list dictionary list-comprehension dictionary-comprehension
1个回答
0
投票
merged = [dict(**c, items=[o for o in oils if o['category_id'] == c['id']]) for c in categories]

from pprint import pprint
pprint(merged)
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