如何使用应用程序脚本设置Google表单问题的转到部分

Question

我有一个Google表单，其中某些字段是“静态”内容，而某些字段是由Google表格中的应用程序脚本填充的，该表格将每天运行。我几乎按我的意愿拥有了它，但是还不够。

我有几个下拉列表，它们需要包含导航到表单不同部分的选项，例如：

Phill / Beacon Hill - Go to section called "Beacon Hill
Jane  / Harbord     - Go to section called "Harbord"
Fred / Beacon Hill  - Go to section called "Beacon Hill"
etc...

正在发生的事情是，我没有将选择追加到列表中，而是覆盖了，这意味着我最终在下拉菜单中只选择了一个，这是最后一个添加的选择，即上例中的Fred。

我已经在网络上查看了很多示例，但无法正常工作。我觉得我已经很近了，但还没到那儿。这是我的代码，有几行我认为是问题所在。有人可以告诉我我要去哪里了。

function populatePlayersClubsListV2() {
// ------------------------------------------------------------------------------------------------
// This gets each male player and the junior club they've been assigned to from the 
// Junior_Clubs_Training_Sessions s/sheet (which is this s/sheet). It creates a list that the player 
// chooses their name from and sets up a branch to the appropriate Club training sessions section 
// in the form depending on which club they're assigned to. .
// ------------------------------------------------------------------------------------------------  

  // Open the "Find Junior Club Training Sessions" form 
  var form = FormApp.openById("1fo33ncgJY.................iRnMsERRTen8WjTH_xrx0");

  // Identify the sheet in this spreadsheet holding the data needed to populate the drop-down. Here 
  // it's the "PlayersClubs" tab which says which club each player is assigned to.
  var ss = SpreadsheetApp.getActive();
  var playersClubsSheet = ss.getSheetByName("PlayersClubs");

  // Grab the values from the rows & columns of the sheet - use 2 to skip header row. Use getMaxRows 
  // and getMaxColumns to avoid hard-coding the number of rows and columns.
  var playersClubsSsValues = playersClubsSheet.getRange(2, 1, playersClubsSheet.getMaxRows() - 1, playersClubsSheet.getMaxColumns() - 1).getValues();

  // We need to loop thro twice - once to populate the male players, and again for the female players.
  // Males/females populate different fields and we hold the data-item-IDs of those fields in an array.
  var formFieldsArray = [
                         ["Male", 1397567108],
                         ["Female", 1441402031]
                        ];

  for(var h = 0; h < formFieldsArray.length; h++) {

    // Open the form field you want to populate - it must be a dropdown or multiple choice.
    // Right-click field, inspect and look for data-item-ID followed by a number.
    var playersClubsFormList = form.getItemById(formFieldsArray[h][1]).asListItem();

    // Define array to hold values coming from the s/sheet and used to populate form fields.
    var playersClubsArray = [];    

    var sectionMalePlayers = form.getItemById(309334479).asPageBreakItem();
    var sectionFemalePlayers = form.getItemById(856495273).asPageBreakItem();

    // Create the array of players and their clubs ignoring empty cells. Check if the s/sheet row  
    // matches male/female against formFieldsArray[h][0].
    for(var i = 0, j = 0; i < playersClubsSsValues.length; i++) {
      if(playersClubsSsValues[i][0] != "" && playersClubsSsValues[i][1] == formFieldsArray[h][0]) {
        playersClubsArray[j] = playersClubsSsValues[i][0] + " - " + playersClubsSsValues[i][2];
        if (formFieldsArray[h][0] = "Male") {
          // ** THIS IS THE LINE THAT OVERWRITES BUT I NEED IT TO APPEND *** //
          playersClubsFormList.setChoices([playersClubsFormList.createChoice(playersClubsArray[j], sectionMalePlayers)]);
        }
        else {
          // ** THIS IS THE LINE THAT OVERWRITES BUT I NEED IT TO APPEND *** //
          playersClubsFormList.setChoices([playersClubsFormList.createChoice(playersClubsArray[j], sectionFemalePlayers)]);
        }

        playersClubsFormList.setChoices([playersClubsFormList.createChoice(playersClubsArray[j], sectionMalePlayers)]);   
        j = j + 1;
      } // end if
    } // end for loop
  } // end for loop for Males/Females 
}

Answer 1

问题：

使用setChoices时，以前存储在项目中的所有选项都将被删除。仅将使用setChoices时指定的内容添加到该项目。

现在，您仅指定一种选择：

playersClubsFormList.setChoices([playersClubsFormList.createChoice(playersClubsArray[j], sectionMalePlayers)]);

解决方案：

您必须指定项目要具有的所有选择。因此，在这种情况下，您将必须执行以下操作：

• 检索先前通过getChoices存储的所有选项。这将检索一个包含该项目中所有当前选择的数组。
• 使用Array.prototype.push()将要添加的选择添加到选择列表。
• [使用setChoices时，应将在步骤1中检索并在步骤2中修改的数组作为参数提供。

代码示例：

更改此：

playersClubsFormList.setChoices([playersClubsFormList.createChoice(playersClubsArray[j], sectionMalePlayers)]);

为此：

var choices = playersClubsFromList.getChoices();
choices.push(playersClubsFormList.createChoice(playersClubsArray[j], sectionMalePlayers));
playersClubsFormList.setChoices(choices);

注意：

• 对于发生此问题的所有行，都必须进行相同的更改，就像这样：

playersClubsFormList.setChoices([playersClubsFormList.createChoice(playersClubsArray[j], sectionFemalePlayers)]);

参考：

• getChoices()
• setChoices(choices)