postgres 中的 PARTITION BY HASH 分区提醒是如何计算的

问题描述 投票:0回答:1

我想手动计算提醒,以便在分区表中使用upsert。 我尝试了以下代码:

create table test_partitioning
(
    test bigint not null
) partition by hash (test);

DO $$
    declare
        _remainder integer ;
    begin
        FOR _remainder IN (select generate_series(1, 10)) LOOP
                EXECUTE 'CREATE TABLE  IF NOT EXISTS  test_partitioning_' || _remainder ||
                        ' PARTITION OF test_partitioning FOR VALUES WITH (modulus 10, remainder ' || (_remainder - 1) || ')';
            END LOOP;
    END $$;

do
$$
    declare
        value bigint ;
        calculated_reminder int;
    begin
        FOR value IN (select generate_series(1, 10)) LOOP
                calculated_reminder = (((hashint8extended(value, 8816678312871386365)::numeric + 5305509591434766563) % 10)::int + 10) % 10;

                if not satisfies_hash_partition('test_partitioning'::regclass, 10, calculated_reminder, value) THEN
                    RAISE 'check failed, value=%, reminder=%', value, calculated_reminder;
                end if;
            end LOOP ;

    end
$$;

在值 2 和 3 上失败。 我的计算有什么问题?

postgresql database-partitioning
1个回答
0
投票

这里是解决方案:

CREATE OR REPLACE FUNCTION unsigned2signed(signed bigint)
RETURNS numeric AS $$
SELECT CASE
           WHEN signed >= 0 THEN signed::numeric
           ELSE 18446744073709551616 + signed
           END
$$ LANGUAGE SQL;

calculated_reminder = ((unsigned2signed(hashint8extended(value, 8816678312871386365)) + 5305509591434766563) % 18446744073709551616) % 10;

顺便说一句,原始解决方案在分区数 = x^2 (2, 4, 8, 16, ...) 的测试中也有效

© www.soinside.com 2019 - 2024. All rights reserved.