我有这张桌子,我想要做的是将最后一行与子实体对齐。
有可能吗?如果是这样,我该怎么办?
我尝试使用此功能,但无法正常工作。我添加了许多<td>
来对齐它,但是我认为有更好的方法。请帮帮我。
我的代码:
<table class="table table-dark table-hover col-lg-6" id="subjects" name="subjects">
<thead>
<tr>
<th>Code</th>
<th>Title</th>
<th>Status</th>
<th>Proffesor</th>
<th>Section</th>
<th>Classroom</th>
<th>Time in</th>
<th>Time out</th>
<th>Units</th>
</tr>
</thead>
<tbody>
<?php
$q1 ="select * from subjects";
$ex1 = mysqli_query($conn,$q1);
$q2 = "SELECT sum(units) AS units from subj_enrolled where studid= '1512345678' ";
$ex2=mysqli_query($conn,$q2);
$fetch = mysqli_fetch_assoc($ex2);
$check = mysqli_num_rows($ex1);
if ($check > 0){
while ($row=mysqli_fetch_assoc($ex1)) {?>
<tr>
<td> <?php echo $row['subjcode'];?></td>
<td> <?php echo $row['subjtitle'];?></td>
<td> <?php echo $row['subjstatus'];?></td>
<td> <?php echo $row['profid'];?></td>
<td> <?php echo $row['section'];?></td>
<td> <?php echo $row['classroom'];?></td>
<td> <?php echo $row['time_in'];?></td>
<td> <?php echo $row['time_out'];?></td>
<td> <?php echo $row['subjunits'];?></td>
</tr>
</tbody>
<tbody>
<?php }?>
<tr>
<td><?php echo "Total units: "; ?></td>
<td> <?php echo $fetch['units'];?></td>
</tr>
<?php }?>
</div>
</tbody>
</table>
尝试使用以下代码: