如何使负输出真的消极？ [关闭]

Question

我像这样计算一个var：

var difference = new - old;

这会输出正数或负数。

然后：

if (difference => 2) {
  text = "2 or more";
} else if (difference < -1) {
  text = "more than 1 behind;
} 

使用此代码，即使difference输出为-5000，我仍然得到2 or more。而它应该是even less than 1。

为什么？以及如何纠正？

Answer 1

似乎右边的运算符是> =而不是=>

Answer 2

=>是js中的箭头函数，参见arrow function

你应该用它

if (difference >= 2) {
      text = "2 or more";
    } else if (difference < -1) {
      text = "more than 1 behind;
    } 

Answer 3

 if (difference >= 2) {
  text = "2 or more";
} else if (difference < -1) {
  text = "more than 1 behind;
} 

Answer 4

这是你的代码插入一个函数。

确保使用不等式>=的数学符号。

function check(difference){
text = "";
if (difference >= 2) {
  text = "2 or more";
} else if (difference < -1) {
  text = "more than 1 behind";
}
return difference + ": " + text;
}


console.log(check(-3))
console.log(check(-2))
console.log(check(-1))
console.log(check(0))
console.log(check(1))
console.log(check(2))
console.log(check(3))
console.log(check(4))
console.log(check(5))

Answer 5

使用比较运算符的正确方法是> =

if (difference >= 2) {
  text = "2 or more";
} else if (difference < -1) {
  text = "more than 1 behind;
}