这是我的 RESX 文件的样子:
Name Value Comments
Rule_seconds seconds seconds
Rule_Sound Sound Sound
我想要的是: 按字符串值命名,如下所示:
public string GetResxNameByValue(string value)
{
// some code to get name value
}
并按如下方式实现:
string str = GetResxNameByValue("seconds");
这样
str
就会回来Rule_seconds
谢谢!
这可行
private string GetResxNameByValue(string value)
{
System.Resources.ResourceManager rm = new System.Resources.ResourceManager("YourNamespace.YourResxFileName", this.GetType().Assembly);
var entry = rm.GetResourceSet(System.Threading.Thread.CurrentThread.CurrentCulture, true, true)
.OfType<DictionaryEntry>()
.FirstOrDefault(e => e.Value.ToString() ==value);
var key = entry.Key.ToString();
return key;
}
进行一些额外的错误检查..
您可以通过密钥直接访问:
public string gtresource(string rulename)
{
string value = null;
System.Resources.ResourceManager RM = new System.Resources.ResourceManager("CodedUITestProject1.Resource1", this.GetType().Assembly);
value = RM.GetString(rulename).ToString();
if(value !=null && value !="")
{
return value;
}
else
{
return "";
}
}
以防万一它可以帮助任何人。这个 ResourceHelper 的灵感来自 jure 和 Mohan Singh Saini。
using System.Collections;
using System.Linq;
using System.Reflection;
using System.Resources;
using System.Threading;
public class ResourceHelper
{
/// <summary>
/// ResourceHelper
/// </summary>
/// <param name="resourceName">i.e. "Namespace.ResourceFileName"</param>
/// <param name="assembly">i.e. GetType().Assembly if working on the local assembly</param>
public ResourceHelper(string resourceName, Assembly assembly)
{
ResourceManager = new ResourceManager(resourceName, assembly);
}
private ResourceManager ResourceManager { get; set; }
public string GetResourceName(string value)
{
DictionaryEntry entry = ResourceManager.GetResourceSet(Thread.CurrentThread.CurrentCulture, true, true).OfType<DictionaryEntry>().FirstOrDefault(dictionaryEntry => dictionaryEntry.Value.ToString() == value);
return entry.Key.ToString();
}
public string GetResourceValue(string name)
{
string value = ResourceManager.GetString(name);
return !string.IsNullOrEmpty(value) ? value : null;
}
}
简单直接的方法是-
var keyValue = Resources.ResourceManager.GetString("AboutTitle");
在上面的“AboutTitle”是“KEY”部分,因此如果您在资源“AboutTitle= About”中,上面的结果为 keyValue = About
我在 VS2019 的一个项目中使用了它。
public static class ResourceManagerHelper
{
public static string GetResourceName(this ResourceManager resourceManager, string value, CultureInfo cultureInfo, bool ignoreCase = false)
{
var comparisonType = ignoreCase ? System.StringComparison.OrdinalIgnoreCase : System.StringComparison.Ordinal;
var entry = resourceManager.GetResourceSet(cultureInfo, true, true)
.OfType<DictionaryEntry>()
.FirstOrDefault(dictionaryEntry => dictionaryEntry.Value.ToString().Equals(value, comparisonType));
if (entry.Key == null)
throw new System.Exception("Key and value not found in the resource file");
return entry.Key.ToString();
}
}
要调用此扩展方法,
var key = Resources.ResourceManager.GetResourceName(value, CultureInfo.InvariantCulture, true);
在这种情况下,我们不想传递资源程序集,而是可以使用特定资源的resourceManager进行调用。
您可以使用此内联代码(c#、ASP.NET MVC)
var _resource = new ResourceManager(typeof(/*your resource*/));
string res = _resource.GetString(/*resource key*/);
我认为这可以帮助你。
这是一个有限的例子:
.
public static string GetLocalizedNameReversed(string value)
{
ResourceManager rm = new ResourceManager($"YourNamespace.YourFolder.YourResourceFileName", assembly);
var entry = rm.GetResourceSet(new CultureInfo("nb-NO"), true, true)
.OfType<DictionaryEntry>()
.FirstOrDefault(e => e.Value.ToString().Equals(value, StringComparison.OrdinalIgnoreCase));
return entry.Key.ToString();
}