如何对重复的 SQL/PSQL 求和

Question

我在如何构建一个查询来对所有重复项进行求和时遇到一些问题，在下面的这个查询中我可以计算所有出现的次数。

---

SELECT COUNT (*) occurrences
FROM back.submission s
GROUP BY s.name
HAVING COUNT(*) > 1 
----------
|# |occurrences|
|1 |     9     |
|2 |     6     |
|3 |     5     |
|4 |     4     |
|5 |     4     |
|6 |     3     |
....

我想知道如何对所有出现的次数求和，我尝试将计数放入 SUM 中，但它不起作用

Answer 1

您想要另一个级别的聚合吗？

SELECT COUNT(occurrences) AS count_of_duplicates, SUM(occurrences) AS sum_of_duplicates
FROM (
    SELECT COUNT (*) occurrences
    FROM back.submission s
    GROUP BY s.name
    HAVING COUNT(*) > 1 
) t

Answer 2

SELECT #,count(*) As Total FROM back.submission GROUP BY # HAVING COUNT(*) > 1;

Answer 3

With CTE
As
(
Select [#],Count([*]) As Total From back.submission Group By [#]
)
select [#],Total From CTE Where Total>1