从我的sql数据库中获取两个数字之间缺少的数字

Question

从我的sql数据库中获取两个数字之间的缺少的数字，起始数字是0000000001和9999999999，在我的表中，我有两列serial_start和serial_end，并且如您在第一个rwo数据中看到的有100和500以及在第二行501和9999999999而我想得到的缺失值是1到99

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Answer 1

您可以使用lead()获取行之间的缺失值，并使用union all引入第一个：

select serial_start + 1, next_ss - 1
from (select t.*,
             lead(serial_start) over (partition by year order by serial_start) as next_ss
      from t
      where year = 2020
     ) t
where next_ss is not null or next_ss <> ss + 1
union all
select 1, min(serial_start) - 1
from t
where year = 2020
group by year
having min(serial_start) <> 1;