Laravel Eloquent 选择 CASE？

Question

有没有 PHP 和 Laravel Eloquent 经验的人可以帮助我解决这个问题？我试图在 raw() 方法中注入一个 CASE...WHEN..END... 。似乎完全被忽视了。现有的文档还没有。我尝试了几种不同的方法，但都没有成功。我正在努力实现这一目标：

SELECT shares.id, ..., 
   CASE WHEN users.id = <CurrentUser> THEN 1 ELSE 0 END AS is_user, 
   ...
FROM <table>
...

源代码如下：

$shares = Share::where('shares.status', '=', SHARE_STATUS_APPROVED)
                    ->where('shares.deleted', '=', '0')
                    ->where('locations.lat', '<=', $nelat)
                    ->where('locations.lat', '>=', $swlat)
                    ->where('locations.lng', '>=', $nelng)
                    ->where('locations.lng', '<=',  $swlng)
                    ->where('users.id', '=',  $user)
                    ->orWhere('shares.connected_user_id', '=',  $user)
                    ->join('users', 'shares.user_id', '=', 'users.id')
                    ->join('locations', 'locations.id', '=', 'users.location_id')
                    ->join('provinces', 'provinces.id', '=', 'locations.province_id')
                    ->join('countries', 'countries.id', '=', 'locations.country_id')
                    ->select('shares.id AS share_id', 'users.id AS user_id', 'shares.connected_user_id', 'shares.original_language_id', 'shares.image',
                        'users.first_name', 'users.last_name', 'users.email',
                        'locations.city', 'provinces.name', 'countries.code',
                        'locations.lat', 'locations.lng',
                        'shares.created_at')
                    ->raw('(CASE WHEN users.id = ' . $user . ' THEN 1 ELSE 0 END) AS is_user')
                    ->orderBy('shares.created_at', 'desc')
                    ->orderBy('users.id', 'asc')
                    ->orderBy('shares.connected_user_id', 'asc')
                    ->get();

Answer 1

将您的

raw()

调用移至

SELECT

语句内：

->select('shares.id AS share_id', 'users.id AS user_id', 'shares.connected_user_id',    
  'shares.original_language_id', 'shares.image',
  'users.first_name', 'users.last_name', 'users.email',
  'locations.city', 'provinces.name', 'countries.code',
  'locations.lat', 'locations.lng',
  'shares.created_at',
  DB::raw('(CASE WHEN users.id = ' . $user . ' THEN 1 ELSE 0 END) AS is_user')
  )
->orderBy('shares.created_at', 'desc')

来自：https://laravel.com/docs/5.4/queries#raw-expressions

Answer 2

您也可以使用

selectRaw

代替。

->selectRaw("shares.id AS share_id, users.id AS user_id , 
    shares.connected_user_id ,    
      shares.original_language_id, shares.image,
      users.first_name, users.last_name, users.email,
      locations.city, provinces.name, countries.code,
      locations.lat, locations.lng,
      shares.created_at,
      (CASE WHEN users.id = {$user} THEN 1 ELSE 0 END) AS is_user)")
    ->orderBy('shares.created_at', 'desc')

Answer 3

最近我创建了一个包，为 Eloquent Query Builder 添加了 CASE 支持。您可以在这里查看：https://github.com/aglipanci/laravel-eloquent-case

使用该包您可以执行以下操作：

use App\Models\Invoice;
use AgliPanci\LaravelCase\Query\CaseBuilder;

$invoices = Invoice::query()
            ->case(function (CaseBuilder $case) {
                $case->when('balance', '<', 0)->then('Overpaid')
                    ->when('balance', 0)->then('Paid')
                    ->else('Balance Due');
            }, 'payment_status')
            ->get();

Answer 4

您可以使用Laravel 查询丰富。查看此页面以获取您需要的文档：

https://laravel-query-enrich.readthedocs.io/en/latest/QE/Advanced/case/