行集的SQL删除语句

Question

我需要通过使用SQL比较表2（仅status =Loaded）来删除表1（4行集）的行集，否则保留该IG的行集。

例如，将删除表1中的IG 10数据，并且IG 60数据将保持与未加载该IG对应的所有状态相同。

Answer 1

您可以尝试以下操作：

DELETE FROM Table1 WHERE NOT IG IN (
  SELECT IG FROM Table2 WHERE Status <> 'Loaded'
)

为了确保删除正确的行，可以先使用以下SELECT：

SELECT * FROM Table1 WHERE NOT IG IN (
  SELECT IG FROM Table2 WHERE Status <> 'Loaded'
)

Answer 2

尝试一下

delete From [TABLE 1]
where IG in
(
Select IG from [TABLE 2] a where not exists(Select 1 From [TABLE 2] b where a.IG  = b.IG and Status not in ('Loaded') )
)

Answer 3

您可以在下面的查询中尝试

DELETE FROM TABLE1 WHERE IG NOT IN (SELECT IG FROM TABLE2 WHERE STATUS = 'ERROR')

Answer 4

使用NOT IN子句：

delete from TB1 where not IG in  (
  select IG from TB2 where status <> 'Loaded'
)