我在Eloquent中遇到了关于删除子模型的问题:当在process2()
中执行时,我仍然有删除的模型,这是不正常的。
namespace App\Models;
use Illuminate\Database\Eloquent\Model;
class Model1 extends Model
{
public function seasons() {
return $this->hasMany('App\Models\Seasons', 'series_id', 'id');
}
}
class Process {
public function process1($model1Instance) {
for($model1Instance->seasons() as $season) {
if(//whatever//) {
$season->delete();
}
}
}
public function process2($model1Instance) {
for($model1Instance->seasons() as $season) {
//At this point I still have the deleted instance
}
}
}
$proc = new Process();
......
$proc->process1($model1Instance);
$proc->process2($model1Instance);
当process1()
从父母中删除模型时,如何在process2()
中删除它?
1.方法:$ model1Instance-> seasons() - > detach($ season);但得到了:Call to undefined method Illuminate\Database\Query\Builder::detach()
2.另一个类我可以制作另一个简单的类来存储这些但我不认为它没关系,虽然我可以设置过滤季节但仍然必须使用Model1实例:
class Model1Copy {
private $seasons;
public function __construct($seasons) {
$this->seasons = $seasons;
}
}
for($model1Instance->seasons() as $season) {
if(//whatever//) {
$season->delete();
} else {
$childs[]=$season;
}
}
$model1Instance->seasons = $childs
}$model->seasons()
返回关系,而$model->seasons
返回映射到模型的季节集合。请尝试以下方法。
public function process1($model1Instance) {
// Iterate over the collection
for($model1Instance->seasons as $season) {
if(condition) {
$model1Instance->seasons()->detach($season);
$season->delete();
}
}
$model1Instance->save();
}
此外,您正在迭代所有模型的所有季节,并删除满足某些条件的季节。如果你一次性摧毁所有季节,那会不会更有效率。类似于以下内容:
$seasons = Season::where(condition)->get();
Season::destroy($seasons);