卡在选项2的while循环中

Question

这是我的代码：

  while type(checkout) == str:
    if checkout == '1':
        while total_price_final<50:
            print('Spend another $',50.00-total_price_final, 'to enjoy free delivery.Else a cost of $10 will be added to your cart if you choose delivery')
            print('Would you like to continue shopping?\n[1]Yes\n[2]No')
            delivery1=input('Please choose an option:')
            while delivery1>'1':
                print('What would you like to do?\n[1]Proceed with delivery\n[2]Proceed without delivery')
                delivery2 = input('Please choose an option:')
                if delivery2<'1' or delivery2>'2':
                    print('Please choose a valid option!')
                if delivery2=='1' or delivery1=='2':
                    print('Alright')
                    break
            if delivery1=='1':
                break
        break
    elif checkout=='2'or delivery1=='1':
        break

我被困在交付1的while循环中（如果我选择选项2，它将使我返回），请帮助。希望能提供任何帮助。谢谢！

Answer 1

我认为您在输入2后无限循环

print('What would you like to do?\n[1]Proceed with delivery\n[2]Proceed without delivery')
                delivery2 = input('Please choose an option:')

这是真的吗？如果是这样，我相信是因为您从未指定delivery2 == 2。

同样，正如chepner所建议的，input（）函数返回str。无需检查checkout

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