ng 服务没有输出

问题描述 投票:0回答:1

我最近将一个存储库克隆到一台新机器上,现在在启动和运行我的开发服务器时遇到了一些问题。当我运行

ng serve
时,终端中没有输出,如下所示。

这对我来说很奇怪,因为当我创建一个新的角度项目并运行相同的命令时,服务器构建成功。我不确定我在这里缺少什么来允许我的服务器构建和运行。

到目前为止我已采取以下步骤:

  • 在全局和本地卸载了@angular/cli,并将其版本与建议的版本一致https://stackoverflow.com/a/39774999/12936248
  • 安装了 angular-devkit/[电子邮件受保护]以匹配我的存储库中的本地版本
  • 匹配原始项目和新项目中的 angular.json,因为
    development
    对象中的
    serve
    字段在原始项目中不存在。

但是这些都不能给这个命令带来输出。有人可以指出我正确的方向,以便我能够解决这个问题吗?下面是我的 package.json,您可以在 https://github.com/andrervincent/nbd

查看我的项目
  "name": "frontend",
  "version": "0.0.0",
  "scripts": {
    "ng": "ng",
    "start": "ng serve",
    "build": "ng build",
    "test": "ng test",
    "lint": "ng lint",
    "e2e": "ng e2e"
  },
  "private": true,
  "dependencies": {
    "@angular-devkit/architect": "^0.1300.4",
    "@angular-devkit/core": "^13.0.4",
    "@angular/animations": "~8.2.14",
    "@angular/cli": "^13.0.4",
    "@angular/common": "~8.2.14",
    "@angular/compiler": "~8.2.14",
    "@angular/core": "~8.2.14",
    "@angular/forms": "~8.2.14",
    "@angular/platform-browser": "~8.2.14",
    "@angular/platform-browser-dynamic": "~8.2.14",
    "@angular/router": "~8.2.14",
    "cors": "^2.8.5",
    "jwt-decode": "^3.1.2",
    "rxjs": "~6.4.0",
    "tslib": "^1.10.0",
    "zone.js": "~0.9.1"
  },
  "devDependencies": {
    "@angular-devkit/build-angular": "~0.803.25",
    "@angular/compiler-cli": "~8.2.14",
    "@angular/language-service": "~8.2.14",
    "@types/jasmine": "~3.3.8",
    "@types/jasminewd2": "~2.0.3",
    "@types/node": "~8.9.4",
    "codelyzer": "^5.0.0",
    "jasmine-core": "~3.4.0",
    "jasmine-spec-reporter": "~4.2.1",
    "karma": "~4.1.0",
    "karma-chrome-launcher": "~2.2.0",
    "karma-coverage-istanbul-reporter": "~2.0.1",
    "karma-jasmine": "~2.0.1",
    "karma-jasmine-html-reporter": "^1.4.0",
    "protractor": "~5.4.0",
    "ts-node": "~7.0.0",
    "tslint": "~5.15.0",
    "typescript": "~3.5.3"
  }
}```
npm angular-cli angular-devkit
1个回答
0
投票

尝试执行“git clean -fdx”,然后通过运行“npm install”来全新安装依赖项。然后只需运行“npm run start”,它将启动项目。

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