我有一个具有auth0登录名的应用。在这种情况下,我还无法弄清楚如何制作t.useRole
。
幸运的是,这很容易复制。 auth0(应用程序)使用相同的过程。它失败的方式与我的应用程序完全相同。
预期结果-用户登录-用户转到仪表板-用户保持登录状态-用户再次进入信息中心(第二项测试)
实际-用户登录-用户转到仪表板-用户不再通过身份验证-用户进入登录页面
import { Role, Selector, ClientFunction } from 'testcafe';
const getPageUrl = ClientFunction(() => window.location.href.toString());
const exampleRole: Role = Role('https://auth0.com/auth/login', async t => {
const userNameInput = Selector('input').withAttribute('name', 'email');
const passwordInput = Selector('input').withAttribute('name', 'password');
const loginButton = Selector('button').withAttribute('name', 'submit');
await t
.wait(5000)
.click(userNameInput)
.typeText(userNameInput, userName)
.click(passwordInput)
.typeText(passwordInput, password)
.click(loginButton);
})
fixture(`SAMPLE`)
.page('https://manage.auth0.com/dashboard')
.beforeEach(async t => {
await t.useRole(exampleRole)
})
test('My first test', async t => {
await t
.expect(getPageUrl()).contains('dashboard')
});
test('My next test', async t => {
await t
.expect(getPageUrl()).contains('dashboard')
})
输出
SAMPLE
√ My first test
× My next test
1) AssertionError: expected
'https://auth0.auth0.com/login?state=***&client=***&protocol=oauth2&response_type=code&redirect_uri=https%3A%2F%2Fmanage.auth0.com%2Fcallback&scope=openid%20profile%20name%20email%20nickname%20created_at'
to include 'dashboard'
```
。click(loginButton)之后添加等待。请查看这是否适合您的情况。
const exampleRole: Role = Role('https://auth0.com/auth/login', async t => {
const userNameInput = Selector('input').withAttribute('name', 'email');
const passwordInput = Selector('input').withAttribute('name', 'password');
const loginButton = Selector('button').withAttribute('name', 'submit');
await t
.wait(5000)
.click(userNameInput)
.typeText(userNameInput, userName)
.click(passwordInput)
.typeText(passwordInput, password)
.click(loginButton);
.wait(10000);
})