Flask_socketIO不与第二个客户端通信

问题描述 投票:0回答:1

我最近开始进入Web套接字,尤其是Flask-SocketIO。我在这个示例项目中玩了一下,让它部分工作。

如果在我的本地浏览器中打开多个选项卡,则滑块会更新并同步所有选项卡,但如果我从其他客户端打开该页面,则浏览器将无法同步。直到其他客户刷新他的页面。

有人可以解释我这种行为吗?我是否误解了一般的网络套接字?

这是我的python / flask代码:

from flask import Flask, render_template
from flask_socketio import SocketIO, emit

app = Flask(__name__)
socketio = SocketIO(app)

values = {
    'slider1': 25,
    'slider2': 0,
}

@app.route('/')
def index():
    return render_template('index.html',**values)

@socketio.on('connect')
def test_connect():
    emit('after connect',  {'data':'Lets dance'})

@socketio.on('Slider value changed')
def value_changed(message):
    values[message['who']] = message['data']
    emit('update value', message, broadcast=True)

if __name__ == '__main__':
    socketio.run(app, host='0.0.0.0')

而我的HTML:

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Synchronized Slider</title>
    <link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.1/css/bootstrap.min.css">
    <script src="https://code.jquery.com/jquery-3.3.1.js"></script>
    <script src="https://cdnjs.cloudflare.com/ajax/libs/socket.io/2.1.1/socket.io.js"></script>
    <script type="text/javascript">
        $(document).ready(function(){

            // sending a connect request to the server.
            var socket = io.connect('http://localhost:5000');

            // An event handler for a change of value 
            $('input.sync').on('input', function(event) {
                socket.emit('Slider value changed', {who: $(this).attr('id'), data: $(this).val()});
                return false;
            });

            socket.on('after connect', function(msg){
                console.log('After connect', msg);
            });

            socket.on('update value', function(msg) {
                console.log('Slider value updated');
                $('#'+msg.who).val(msg.data);
            });
        });
    </script>
</head>
<body>
    <div class="container text-center">
        <h1 >Slider Demo</h1>
        <form class="mt-5">
          <div class="form-group">
            <label for="formControlRange">Demo Slider 1</label>
            <input type="range" class="form-control-range sync" id="slider1" min="0" max="50" value="{{slider1}}">
          </div>
          <div class="form-group">
            <label for="formControlRange">Demo Slider 2</label>
            <input type="range" class="form-control-range sync" id="slider2" min="0" max="50" value="{{slider2}}">
          </div>
        </form> 
    </div>
</body>
</html>

提前致谢! :)

python flask websocket flask-socketio
1个回答
0
投票

弄清楚了。

var socket = io.connect('http://localhost:5000');

当然其他人不会在localhost上运行服务器。

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