如何在 javascript 中合并子数组中的对象，以便在一个数组中留下多个对象

Question

我在 ARRAY 1 中完整地看到了以下数组，我需要每个子数组合并其中的对象，使其像这样。

阵列决赛

---

[
  {"col0":"glasses","col1":"Milky glasses","col2":"292516467012796941"}
  , ...
]

---

所以最终结果是一个包含 6 个对象的数组。上面的...代表其余的对象。

我已经尝试过

[].concat.apply([], array)

，但它并没有达到我想要的效果。我将在 ARRAY 2 的这个数组下面发布它的作用

阵列1

[
  [
    {
      "col0": "Glasses"
    },
    {
      "col1": "Milky Glasses"
    },
    {
      "col2": "292516467012796941"
    }
  ],
  [
    {
      "col0": "Knives"
    },
    {
      "col1": "Milky Knives"
    },
    {
      "col2": "292516484536599049"
    }
  ],
  [
    {
      "col0": "Forks"
    },
    {
      "col1": "Milky Forks"
    },
    {
      "col2": "292516497196057096"
    }
  ],
  [
    {
      "col0": "Gloves"
    },
    {
      "col1": "Kewl Gloves"
    },
    {
      "col2": "292534063457108493"
    }
  ],
  [
    {
      "col0": "Wrench"
    },
    {
      "col1": "Kewl Wrench"
    },
    {
      "col2": "292534088244396552"
    }
  ],
  [
    {
      "col0": "Monkey snake"
    },
    {
      "col1": "Kewl Monkey snake"
    },
    {
      "col2": "292534109863936521"
    }
  ]
]

这是我不想要的输出，但迄今为止我所能做到的。在 ARRAY FINAL 的顶部查看我想要的输出

阵列2

[
  {
    "col0": "Glasses"
  },
  {
    "col1": "Milky Glasses"
  },
  {
    "col2": "292516467012796941"
  },
  {
    "col0": "Knives"
  },
  {
    "col1": "Milky Knives"
  },
  {
    "col2": "292516484536599049"
  },
  {
    "col0": "Forks"
  },
  {
    "col1": "Milky Forks"
  },
  {
    "col2": "292516497196057096"
  },
  {
    "col0": "Gloves"
  },
  {
    "col1": "Kewl Gloves"
  },
  {
    "col2": "292534063457108493"
  },
  {
    "col0": "Wrench"
  },
  {
    "col1": "Kewl Wrench"
  },
  {
    "col2": "292534088244396552"
  },
  {
    "col0": "Monkey snake"
  },
  {
    "col1": "Kewl Monkey snake"
  },
  {
    "col2": "292534109863936521"
  }
]

感谢您提前提供帮助

Answer 1

您可以映射数组并展开对象以获得单个对象。

const
    data = [[{ col0: "Glasses" }, { col1: "Milky Glasses" }, { col2: 292516467012796900 }], [{ col0: "Knives" }, { col1: "Milky Knives" }, { col2: 292516484536599040 }], [{ col0: "Forks" }, { col1: "Milky Forks" }, { col2: 292516497196057100 }], [{ col0: "Gloves" }, { col1: "Kewl Gloves" }, { col2: 292534063457108500 }], [{ col0: "Wrench" }, { col1: "Kewl Wrench" }, { col2: 292534088244396540 }], [{ col0: "Monkey snake" }, { col1: "Kewl Monkey snake" }, { col2: 292534109863936500 }]],
    result = data.map(a => Object.assign({}, ...a));
    
console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 2

这可以像这样完成，

arr

是你的原始数组-

for (let i = 0; i < arr.length; i++) {
  let res = {}, subArr = arr[i];
  subArr.forEach((a,ind) => {
Object.assign(res,subArr[0],subArr[1],subArr[2]);
  });
  arr[i] = res;
}

Answer 3

Nina 给出了最好的答案，但值得注意的是 Object.assign() 是一个浅拷贝。

如果 col 属性本身就是对象，您可以使用如下方法：

const finish = start.map((x) => ({
  ...x[0],
  ...x[1],
  ...x[2]
}));

如果我理解正确的话，...x[0] 语法创建 x[0] 的深层副本，然后我们将其直接分配给新对象，而 Object.assign() 创建浅层副本。