spark-excel dataype问题

问题描述 投票:1回答:1

我正在使用spark-excel程序包使用Spark 2.2处理ms excel文件。除以下异常外,某些文件无法作为spark数据帧加载。如果有人遇到此问题,您能帮忙解决此类数据类型问题吗?

[分析后,我发现如果列名不是字符串,则最终出现以下异常;如果我手动将列名从整数更改为字符串,则可以正常工作。

代码:

  val excelDF = spark.read.
    format("com.crealytics.spark.excel").
    option("useHeader", "true").
    option("treatEmptyValuesAsNulls", "true").
    option("inferSchema", "true").
    option("addColorColumns", "False").
    option("sheetName", sheetName).
    load(filePath)

Exception:

java.lang.IllegalStateException: Cannot get a STRING value from a NUMERIC cell
    at org.apache.poi.xssf.usermodel.XSSFCell.typeMismatch(XSSFCell.java:1077)
    at org.apache.poi.xssf.usermodel.XSSFCell.getRichStringCellValue(XSSFCell.java:395)
    at org.apache.poi.xssf.usermodel.XSSFCell.getStringCellValue(XSSFCell.java:347)
    at com.crealytics.spark.excel.ExcelRelation$$anonfun$inferSchema$1$$anonfun$10.apply(ExcelRelation.scala:206)
    at com.crealytics.spark.excel.ExcelRelation$$anonfun$inferSchema$1$$anonfun$10.apply(ExcelRelation.scala:205)
    at scala.collection.TraversableLike$$anonfun$map$1.apply(TraversableLike.scala:234)
    at scala.collection.TraversableLike$$anonfun$map$1.apply(TraversableLike.scala:234)
    at scala.collection.Iterator$class.foreach(Iterator.scala:893)
    at scala.collection.AbstractIterator.foreach(Iterator.scala:1336)
    at scala.collection.IterableLike$class.foreach(IterableLike.scala:72)
    at scala.collection.AbstractIterable.foreach(Iterable.scala:54)
    at scala.collection.TraversableLike$class.map(TraversableLike.scala:234)
    at scala.collection.AbstractTraversable.map(Traversable.scala:104)
    at com.crealytics.spark.excel.ExcelRelation$$anonfun$inferSchema$1.apply(ExcelRelation.scala:205)
    at com.crealytics.spark.excel.ExcelRelation$$anonfun$inferSchema$1.apply(ExcelRelation.scala:204)
    at scala.Option.getOrElse(Option.scala:121)
    at com.crealytics.spark.excel.ExcelRelation.inferSchema(ExcelRelation.scala:204)
    at com.crealytics.spark.excel.ExcelRelation.<init>(ExcelRelation.scala:91)
    at com.crealytics.spark.excel.DefaultSource.createRelation(DefaultSource.scala:37)
    at com.crealytics.spark.excel.DefaultSource.createRelation(DefaultSource.scala:14)
    at com.crealytics.spark.excel.DefaultSource.createRelation(DefaultSource.scala:8)
    at org.apache.spark.sql.execution.datasources.DataSource.resolveRelation(DataSource.scala:306)
    at org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:178)
    at org.apache.spark.sql.DataFrameReader.load(DataFrameReader.scala:156)
excel apache-spark apache-spark-sql apache-poi spark-excel
1个回答
0
投票

对此可能有一个更优雅的答案,我将其发布为评论,但没有所需的声誉。

我总是尝试确保列标题是字符串。

通常,我在列标题中也没有数字字符,并且我们有一个简单的脚本,用字母字符(即1到1)替换数字。

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